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3 years ago

Can you always put two triangle together to make a rectangle? Explain why or why not.

1 answer:

6 0

no, since a rectangle requires 90-degree corners, and every angle inside an equilateral triangle is 60-degrees. The only multiple of 90 that you can make is 180-degrees (or any multiple of it).

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PLZ QUICK!!

iragen [17]

Answer:

See attached graph

Step-by-step explanation:

The equation is y-3=(x + 6)

Write the equation in a slope intercept form, then graph the equation on a graph tool to see the points that line on the line.

Alternatively , using the coordinates in the answer choices given, input them in the equation of the graph and select the answer choice that has all its coordinates true to the equation.

y-3 = x+6 -----can be written as : y= x+9

Graph y= x+9 to see the graph and the points that are on the line as attached.

3 0

3 years ago

Read 2 more answers

A . it is increasing and linear

Paha777 [63]

Answer:

The answer is B.

Step-by-step explanation:

From the interval -6 < x < 0, the line is straight which is linear equation. The line shows its going down so it will be decreasing gradient.

8 0

3 years ago

A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c

olchik [2.2K]

The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in $E^{c}$ . Find $P(E^{c})$ .

Solution:

Part 1:

$E^{c}$ means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

$E^{c}=S-E \\ \\ 
E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\ \\ 
E^{c}=(4,5,6)$

Thus the set compliment of E will contain the elements {4,5,6}.So

$E^{c}$ = {4,5,6}

Part 2)

$P(E^{c})$ means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

$P(E^{c})$ = (Number of Elements in $E^{c}$ )/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set $E^{c}$ = $n(E^{c})$ =3

So,

$P(E^{c})= \frac{n(E^{c}) }{n(S)} \\ \\ 
P(E^{c})= \frac{3}{12} \\ \\ 
P(E^{c})= \frac{1}{4}$

7 0

3 years ago

Given m | n, find the value of x. m n 68 (6x+8)

BARSIC [14]

Answer:

As 6x+8 = 68

=> x = 10

Hope it helps

4 0

3 years ago

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Solve the equation m²+4m=-2

UNO [17]

Step 1: Subtract -2 from both sides.
m2+4m−(−2)=−2−(−2)
m2+4m+2=0
Step 2: Use quadratic formula with a=1, b=4, c=2.
m=−b±√b2−4ac2a
m=−(4)±√(4)2−4(1)(2)2(1)
m=−4±√82
m=−2+√2 or m=−2−√2

4 0

4 years ago

Read 2 more answers