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Lerok [7]
2 years ago
13

The choices are a) 36xy^3 b) 36xy^2 c) 36xy d) 36x^2y^6

Mathematics
2 answers:
N76 [4]2 years ago
7 0
A. take the ^2 off x then do the same 3 times to Y

trapecia [35]2 years ago
5 0
Answer is <span>a) 36xy^3

hope that helps</span>
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Please answer #1 and #2
DIA [1.3K]
1)
x^2 + (3y/2z) = 7
2x^2z + 3y = 14z
3y = 14z - 2x^2z
3y = 2z(7 - x^2)
  y = 2/3(z)(7 - x^2)

2)
(3zx^4) /(5+z) = 2y
3zx^4 = 2y(5+z)
3zx^4 = 10y + 2yz

6 0
2 years ago
(x^3)^9 = <br> A: x^12 <br> B: x^27 <br> C: x^3 <br> D: x^6
Grace [21]
(x^3)^9=x^{27}
3 0
3 years ago
Insert parentheses to make the statement true <br> 21-8-6=7
Advocard [28]

(21-8)-6=7

and that's it

5 0
2 years ago
PLEASE HELP I GIVE THANKS
drek231 [11]
A, C, And D

Could be these answers...
7 0
3 years ago
g Nationwide, a certain disease occurs only a small proportion of people (.000215). A certain town has 74,000 residents. Use the
Andrei [34K]

Answer:

The probability that the town has 30 or fewer residents with the illness = 0.00052.

Step-by-step explanation:

So, we have the following set of data or information or parameters given from the question above and they are; the number of people living in that particular society/community/town = 74,000 residents and the proportion of people that the diseases affected = .000215.

The first step to do is to determine the expected number of people with disease. Thus, the expected number of people with disease = 74,000 × .000215 = 15.91.

Hence, the probability that the town has 30 or fewer residents with the illness = 1.23 × 10^-7 × 15.91^30/ 2.65253 × 10^-32 = 0.00052.

Note the formula used in the calculating the probability that the town has 30 or fewer residents with the illness =  e^-λ × λ^x/ x!

8 0
2 years ago
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