Question

Need help! Law of cosines...find b round to the nearest tenth please

Answer 1

ANSWER

$B = 27.8 \degree$

EXPLANATION

The law of cosine is given by the formula:

${b}^{2} = {a}^{2} + {c}^{2} - 2bc \cos(B)$

From the diagram,

a=17, b=8, c=16

We substitute the given values into the formula to obtain:

${8}^{2} = {17}^{2} + {16}^{2} - 2(17)(16)\cos(B)$

$64 = 289+ 256- 544\cos(B)$


$64 = 545- 544\cos(B)$


$64 - 545 = - 544\cos(B)$

$- 481 = - 544\cos(B)$

$\frac{ - 481}{ - 544} = \cos(B)$

$cos(B) = 0.88419$

$B = \cos ^{ - 1} (0.88419)$

$B = 27.8 \degree$

Answer 2

Answer:

what would A be ?

Step-by-step explanation: