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SSSSS [86.1K]
3 years ago
9

Multiply the equation (t-7)^3

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
3 0
(t - 7)³
(t - 7)(t - 7)(t - 7)
(t² - 7t - 7t + 49)(t - 7)
(t² - 14t + 49)(t - 7)
(t³ - 7t² - 14t² + 98t + 49t - 343)
t³ - 21t² + 147t - 343
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Answer:

  • a) AB = 10 units
  • b) Midpoint is (2, 6)

===================

<h3 /><h3>Given</h3>

  • Points A( - 1, 10) and B(5, 2)

<h3>To find</h3>

  • a) The length of AB
  • b) The midpoint of AB

<h3>Solution</h3>

a) Use the distance formula:

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates and calculate:

d=\sqrt{(5-(-1))^2+(2-10)^2} =\sqrt{6^2+(-8)^2} =\sqrt{36+64} =\sqrt{100} =10

The distance is AB = 10 units

b) Use midpoint formula and find x and y- coordinates of this point:

x= \cfrac{x_1+x_2}{2}    and    y= \cfrac{y_1+y_2}{2}

Substitute coordinates and find the midpoint:

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The midpoint is (2, 6)

3 0
2 years ago
Read 2 more answers
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