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vodka [1.7K]
4 years ago
6

How many triangles can be constructed with sides measuring 14 cm, 8 cm, and 5 cm?

Mathematics
2 answers:
V125BC [204]4 years ago
8 0
The answer would be one
babymother [125]4 years ago
6 0
The answer is 3 triangles
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Kenny is 5 feet 5inches, while Lamar is 67 inches. Who is taller
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Complete the equation to make a true statement. 12,000 lb = ____ T
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A cube of side length s sits inside a sphere of radius r so that the vertices of the cube sit on the sphere. Find the ratio r :
svlad2 [7]

Answer:

r : s is √3 : 2

Step-by-step explanation:

The given parameter are;

A cube is inscribed in a sphere

The side length of the cube = s

The radius of the sphere = r

The ratio r : e = Required

It is noted that for a cube inscribed in a sphere, we have;

The diameter of the sphere = The diagonal of the cube

The diameter of the sphere, D = 2 × The radius = 2·r

The square of the diagonal of the cube, d² = s² + s² + s² = 3·s²

∴ The diagonal of the cube, d = (√3)·s

From the relationship between the cube and the sphere in which it is inscribed, (The diameter of the sphere = The diagonal of the cube), we have;

2·r = (√3)·s

∴ r/s = (√3)/2

r : s = √3 : 2.

8 0
3 years ago
Factor the trinomial 8x^2-12x-8
fgiga [73]

Answer:

(x-2)(8x+4)

Step-by-step explanation:

we have

8x^{2} -12x-8

Equate to zero and find the roots of the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

8x^{2} -12x-8=0

so

a=8\\b=-12\\c=-8

substitute in the formula

x=\frac{-(-12)(+/-)\sqrt{-12^{2}-4(8)(-8)}} {2(8)}

x=\frac{12(+/-)\sqrt{400}} {16}

x=\frac{12(+/-)20} {16}

x_1=\frac{12(+)20} {16}=2

x_2=\frac{12(-)20} {16}=-\frac{1}{2}

therefore

8x^{2} -12x-8=8(x-2)(x+\frac{1}{2})=(x-2)(8x+4)

8 0
3 years ago
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