I’m not sure if your answer is right but here’s how to solve it
2 n/3 would be the closest answer although it looks as if the 2 is supposed to be multiplied by n/3 which would lead me to write it as 2(n/3)
Answer:
The expected number of times is 4.
Step-by-step explanation:
Looking at the question, we see that this follows a geometric distribution because it is asking for the expected number of trials hat will bring about the FIRST SUCCESS. The probability of success is
Since it is a geometric distribution, we know that the expected value of a random variable X, E(X) that follows a geometric distribution is given as:
E(X) = 1/p where p is the probability of success.
Therefore, the expected number of times will be
E(X) = 1/(1/p) = 1/(1/4) = 4.
Hence, the expected number of times is 4.
A line parallel and passing through point (1,5) would be y=-3x+8