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Anvisha [2.4K]
2 years ago
11

The factorial 4! is equal to

Mathematics
2 answers:
timofeeve [1]2 years ago
8 0

Answer:

24

Step-by-step explanation:

the reason the answer is 4 is because the factorial is made up of the all the numbers from 1 to the number that you are trying to find the factorial for. For example, 4 is gonna be 1 x 2 x 3 x 4=24

Maru [420]2 years ago
6 0
Pay attention cause the factorial will be like this:
<span>4!=4∗3∗2∗1
And the consequent answer will be 24
Hope this works for you</span>
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Could 13 15 and 19 be a right triangle
Nat2105 [25]

Answer:

No b/c the hypotenuse is too short

Step-by-step explanation:

13² + 15² = 19²

169 + 225 = 361

394 ≠ 361

6 0
3 years ago
35.6 = the square root of 15.3^2 + the square root of x^2. Find x.​
vivado [14]

Answer:

x = 50.9

Step-by-step explanation:

35.6 = √(15.3²) + √(x²)

35.6 = 15.3 + x

x = 35.6 + 15.3

x = 50.9

5 0
2 years ago
Circle O has a circumference of 88π cm.
Ratling [72]

Answer:

44 cm

Step-by-step explanation:

Half of the diameter is the radius so half 88 to get 44 since 88 is the diameter.

4 0
2 years ago
Read 2 more answers
The measure of ∠1 is 65°. What is the relationship between ∠1 and ∠2
bagirrra123 [75]

Answer:

if its complemantary it is 24 degrees

if it supplemntary it is 115 degrees

Step-by-step explanation:

7 0
3 years ago
Solve the system by using a matrix equation (Picture provided)
Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]

A= \left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]

X= \left[\begin{array}{c}x\\y\end{array}\right]

B= \left[\begin{array}{c}4\\2\end{array}\right]

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

                                    = (-42)-(-40)

                                    = (-42) + 40 = -2

so, |A| = -2

Adj A=  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]

A⁻¹ =  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]/ -2

A⁻¹ =  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]

X= A⁻¹ B

X=  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]

X= \left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]

X= \left[\begin{array}{c}12-4\\20-7\end{array}\right]

X= \left[\begin{array}{c}8\\13\end{array}\right]

x= 8, y= 13

solution set= (8,13).

Option b is correct.

3 0
3 years ago
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