PART1:
First Combination:
Pizza ($7) + Chicken Strips ($6) + Biscuits ($3) + Grapes ($4) = $20
Second Combination:
Dog Food ($13) + Bread ($3) + Crackers ($2) + Broccoli ($2) = $20
Third Combination:
Shampoo ($4) + Tissues ($3) + Pizza ($7) + Eggs ($3) + Biscuits ($3) = $20
PART 2:
First Combination:
$7.20 + $5.70 + $2.90 + $3.70 = $19.60
No, I wouldn’t have gone over the limit
Second Combination:
$13.40 + $3.50 + $2.00 + $1.90 = $20.80
Yes, I would have gone over the limit
Third Combination:
$3.50 + $2.60 + $7.20 + $2.50 + $2.90 = $18.70
No, I wouldn’t have gone over the limit
Hope this helps!!
Answer:
The answer is "".
Step-by-step explanation:
Please find the complete question in the attached file.
We select a sample size n from the confidence interval with the mean
and default
, then the mean take seriously given as the straight line with a z score given by the confidence interval

Using formula:
The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution
the required probability:

Answer:
P(t) = 14300e^0.07t
Step-by-step explanation:
Let :
Population as a function of years, t = P(t) ;
Growth rate, r = 7%
Estimated population on year 2000 = Initial population = 14300
The given scenario can be modeled using an exponential function as the change in population is based in a certain percentage increase per period.
P(t) = Initial population*e^rt
P(t) = 14300*e^(0.07t)
P(t) = 14300e^0.07t
Where, t = number of years after year 2000.
Hey there, just multiply 2.2 by 5, 2.2×5=11. Therefore, the lowest common multiple of 2.2 and 5 is 11.
18 is 6+n. The other one is 60 because n=60 and 60+6=66. 66 represents Chang's height.