All categories

2 years ago

Which graph shows y= (-5x) -4?

Mathematics

1 answer:

Leya [2.2K]2 years ago

6 0

Answer:

Graph A

Step-by-step explanation

I look at the y-intercept first, and the y-intercept is -4, so looking at each graph you can see both A and D have y-intercepts of -4, since the line intercepts, or goes through the y-axis (the vertical line of the graph) at -4.

Then, you look at the variable that's changing, which is -5x. Since it's a negative, A is the graph that is negatively decreasing, because of its position on the graph. The line is going down, starting in the negative side.

You might be interested in

Do the ratios 30/24 and 20/16 form a proportion?

BartSMP [9]

Answer:

Yes.

Step-by-step explanation:

Reduce both fractions.

30/24 = 5/4
20/16= 5/4

6 0

3 years ago

Hello please answer ASAP i will give brainliest.

iragen [17]

Answer:

Step-by-step explanation:

There is a pattern. Subtract input from output and it is 11. So, if 11 is the pattern. subtract 51 from A,B,C, and D.Till one of them has the number 11 as answer. 51- 40=11. 40 = B

7 0

2 years ago

Read 2 more answers

Question 9 Multiple Choice Worth 1 points)

beks73 [17]

Answer: $\bold{10 = \sqrt {\left( {x- 8 } \right)^2 + \left( {y - 9 } \right)^2 }}$

Step-by-step explanation:

Given:

The coordinates of Point A: (8, 9)

The coordinates of Point B are unknown: (x, y)

The distance from A to B is 10 units

Then, using the distance formula:

$AB = \sqrt {\left( {x- 8 } \right)^2 + \left( {y - 9 } \right)^2 }$

Therefore,

$10 = \sqrt {\left( {x- 8 } \right)^2 + \left( {y - 9 } \right)^2 }$

8 0

1 year ago

Find the 15th term of the arithmetic sequence 13,8,3,-2

Lunna [17]

Answer:

-57

Step-by-step explanation:

13,8,3,-2 (decreasing by 5)

13,8,3,-2,-7,-12,-17,-22,-27,-32,-37,-42,-47,-52,-57.

The 15th term is -57.

Ace

4 0

2 years ago

When does expanding and simplifying a(b+c) result in a positive value for ac

TiliK225 [7]

Answer:

Step-by-step explanation:

(ab + bc)(ab + bc)

Simplifying

(ab + bc)(ab + bc)

Multiply (ab + bc) * (ab + bc)

(ab(ab + bc) + bc(ab + bc))

((ab * ab + bc * ab) + bc(ab + bc))

Reorder the terms:

((ab2c + a2b2) + bc(ab + bc))

(ab2c + a2b2 + (ab * bc + bc * bc))

(ab2c + a2b2 + (ab2c + b2c2))

Reorder the terms:

(ab2c + ab2c + a2b2 + b2c2)

Combine like terms: ab2c + ab2c = 2ab2c

(2ab2c + a2b2 + b2c2)

7 0

3 years ago