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pashok25 [27]
2 years ago
15

HELPPPPPPPPPP!!!!!!!!!!!!!

Mathematics
1 answer:
kondaur [170]2 years ago
5 0

A. true

B. false

C. false

D. false

hope it helps

have a good day :)

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The sum of 2 numbers is 38. one number is 10 more than the other.
son4ous [18]

Answer:

24, 14

Step-by-step explanation:

x + y = 38

x = 10 + y

You can substitute (10+y) into the top equation where the x is.

10 + y + y = 38

10 + 2y = 38

2y = 28

y = 14

Now plug 14 in for y in either equation to get x

x = 10 + 14

x = 24

8 0
3 years ago
A parachutist's speed during a free fall reaches 180 kilometers per hour. What is this speed in meters per second? At this speed
Darya [45]

Answer:

Speed of the parachutist is meters per second 2.083 meter per second

Distance travelled in 2 seconds 4.167 meter

Step-by-step explanation:

Speed of the parachutist is kilometers per hour = 180

Speed of the parachutist is meters per second \frac{180*1000}{24*60*60} = 2.083 meter per second

Distance travelled in 2 seconds 2.083 *2 = 4.167 meter

8 0
3 years ago
PLEASE LOOK AT PHOTO! WHOEVER ANSWERS CORRECTLY I WILL MARK BRAINIEST!!
marissa [1.9K]

Answer:

53°

Step-by-step explanation:

It is given that the total measurement of the two angles combined would equate to 116°.

It is also given that m∠WXY is 10° more then m∠ZXY.

Set the system of equation:

m∠1 + m∠2 = 116°

m∠1 = m∠2 + 10°

First, plug in "m∠2 + 10" for m∠1 in the first equation:

m∠1 + m∠2 = 116°

(m∠2 + 10) + m∠2 = 116°

Simplify. Combine like terms:

2(m∠2) + 10 = 116

Next, isolate the <em>variable</em>, m∠2. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 10 from both sides of the equation:

2(m∠2) + 10 (-10) = 116 (-10)

2(m∠2) = 116 - 10

2(m∠2) = 106

Next, divide 2 from both sides of the equation:

(2(m∠2))/2 = (106)/2

m∠2 = 106/2 = 53°

53° is your answer.

~

8 0
2 years ago
Read 2 more answers
The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum? ​
VLD [36.1K]

Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that

<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>

<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>

where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.

Then the sum is

<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>

and its magnitude is

||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

5 0
3 years ago
Read 2 more answers
Nora uploaded a funny video on her website, which rapidly gains views over time. The relationship between the elapsed time, ttt,
inysia [295]

Answer:

grows by a factor of 1.53

7 0
2 years ago
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