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Zanzabum
3 years ago
13

PLEASE HELP.....................................................................................................................

...........................................................................................................................................................................

Mathematics
2 answers:
Assoli18 [71]3 years ago
3 0
I believe it is WW and WL for the top row and LW and LL for the second one. This kind of reminds me of punnett squares.
neonofarm [45]3 years ago
3 0
The top row would be      WW WL
The bottom row would be WL  LL
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The product of $7d^2-3d+g$ and $3d^2+hd-8$ is $21d^4-44d^3-35d^2+14d-16$. What is $g+h$?
galina1969 [7]
<h2>Answer:</h2><h2>g = 2  and h = -5</h2>

Step-by-step explanation:

To find the product with unknown values of variables, multiply the terms and equate the value to the given product.

(7d^{2} - 3d + g)(3d^{2} + hd - 8) = 21d^{4}  + 7hd^{3} - 56d^{2} - 9d^{3} - 3hd^{2} + 24d + 3gd^{2} + ghd - 8g

(7d^{2} - 3d + g)(3d^{2} + hd - 8)     = 21d^{4}  + (7h-9) d^{3} + (3g-56-3h)d^{2}  + (24+gh)d -8g   ... (1)

Comparing eq(1) to the product given in question,

-8g = -1

g = 2

24 + gh = 14, sub g =2,

24 + 2h = 14

h = -5

3 0
3 years ago
Help on this question explain my answer please!
Tresset [83]
0.12 x 70 = 8.4

12% of 70 is 8.4
5 0
3 years ago
What is the decimal for 2/3
lakkis [162]
0.6 repeating (AKA 0.6666666-----)
7 0
3 years ago
3. A mechanic charges $90 for the inspection plus $25 per hour. If the bill was $240, how many hours did he work?
notka56 [123]
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7 0
3 years ago
Arc AD=98 and I need help with both problems below
Anni [7]

Answer:

arc DC = 64

angle DCQ = 32

Step-by-step explanation:

Hello There!

The circumference of a normal circle is 360

Given that arc AD = 98 and having found arc ABC we can find arc DC by subtract the known arcs from 360

360 - 98 - 198 = 64

Hence arc DC = 64

The problem wants us to find angle DCQ having found arc DC

Remember like stated before an included angle is equal to 1/2 its opposite arc

64/2=32

so angle DCQ = 32

5 0
2 years ago
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