B is your awnser! sorry if im wrong my calc shows its without a - symbol
Answer:
-15
Step-by-step explanation:
g(x) = 3x + 3
Let x = -6
g(-6) = 3*-6 + 3
= -18 +3
= -15
This triangle has 60 degrees already. Remember that the sum of all triangles have to be 180.
Since we have two y's we can simplify it as 2y + 60 = 180.
We can now set this up as an algebraic equation.
2y + 60 = 180
Subtract 60 from both sides.
2y = 120
Divide both sides by 2
y = 60.
Y = 60, your answer is D.)
I hope this helps!
Answer:
356 ft³ per month.
Step-by-step explanation:
From the question,
Water flows at a rate of 710 pints per day.
We shall convert 710 pints to cubic feet (ft³).
This can be obtained as follow:
1 pint = 0.0167 ft³
Therefore,
710 pints = 710 × 0.0167 = 11.857 ft³
From the calculations made above, 710 pints is equivalent to 11.857 ft³.
Thus, we can say that water flows at a rate of 11.857 ft³ per day.
Finally, we shall determine the rate of flow of water in cubic feet per month.
Note: there are 30 days in a month.
Water flow at a rate of 11.857 ft³ per day.
Therefore, the rate of flow of water in 30 days will be = 30 × 11.857 ft³ = 356 ft³
Thus, the flow rate of water is 356 ft³ per month.
Answer:
103= p small
plarge = 123
Step-by-step explanation:
We know that the the ratio of the areas is the scale factor squared/
Larger triangle over smaller triangle
72
----- = scale factor ^2
50
simplify by dividing by 2 on top and bottom
36
----- = scale factor ^2
25
Take the square root of each side
sqrt(36)
-------------- = sqrt(scale factor ^2)
sqrt(25)
6
-------------- = scale factor
5
The ratio of the perimeters is the scale factor
p large 6
-------------- = ----------------
p small 5
Using cross products
6 p large = 5 p small
We know the sum is 226
p large + p small = 226
p large = 226 - p small
We have 2 equation and 2 unknowns
6 p large = 5 p small
Substitute for p large
6 (226 - p small) = 5 p small
1356 - 6 p small = 5 p small
Add 6 p small to each side
1356 = 11 p small
divide by 11
1356/11 = p small
P large = 226-1356/11
p large = 2486/11-1356/11
plarge = 1130/11
The solution requires whole number answers so
1356/11 = p small
123.27 which rounds to 123
plarge = 1130/11
plarge = 102.7272 = 103
