Answer:
I hope it will help you..
For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
<span>2tan^2 x + tan^2 x - 1 = 0 or
</span>3 tan^2 x = 1.
So x = pi/2, pi/2 + pi = 3pi/2.
Set up a ratio:
You drove 72 minutes and 100 km = 72/100
You want the number of minutes (x) to drive 150 km = x/150
Set the ratios to equal each other and solve for x:
72/100 = x/150
Cross multiply:
(72 * 150) = 100 * x)
Simplify:
10,800/100x
Divide both sides by 100:
x = 10800/100 = 108
This means it would take 108 minutes to drive 150 km.
Now subtract the time you have already driven to fin how much more you need:
180 - 72 = 36 more minutes.
Answer:
12.5%
Step-by-step explanation:
In order to find the percentage the worker spent traveling, we can make us of the following ratio:

where number is how many hours he spent traveling, ammount is the total ammount of hours he reported and percent is the percentage we want to find. So we can solve the ratio for the percent, so we get:

now, we need to find the total amount of hours he spent traveling, this is gotten by adding the provided data:
6hrs+5hrs=11hrs
next we need to find the total amount of hours reported:
42hrs+46hrs=88hrs
so now we can substitute the data the problem provided us with:

which yields:
percent=12.5%
27/100 because you can't simplify 27 and 100 so it's just 27/100