Answer:
50.40% probability that all 4 are different.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Desired outcomes:
4 digits, all different
For the first digit, it can be any of them, so there are 10 possible
For the second digit, it can be any of them other than the first digit. So there are 9 possible.
For the third digit, it can be any of them, other than the first and the second. So there are 8 possible.
By the same logic, 7 possible digits for the fourth. So
Total outcomes:
4 digits, each can be any of them(10 from 0 - 9).
So
Probability:
50.40% probability that all 4 are different.
Answer:
<1 = 48
Step-by-step explanation:
<1 + <2 + <3 = 180 since they form a line
<1 + 90+ 42 =180
Combine like terms
<1 + 132 =180
Subtract 132 from each side
<1 +132-132 =180-132
<1 = 48
If your question is how many positions are possible, then the answer is 24.
We find this by thinking of how many people can be in each spot. If there are 4 spots each person can stand (back left, back right, front left, front right), then there are 4 possible choice for the first spot (mom, dad, son, daughter), then 3 for the next spot (since 1 is already in a spot), then 2 options for the next spot, and then 1 option for the last spot. In other words, the answer is 4x3x2x1, or 4 factorial.
This shape is trapezoid
top of the trapezoid is 10 (12-2)
and the bottom is 4 (6-2)
the height in 3 (3-0)
so the area will be
the area is 21
