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Sav [38]
4 years ago
15

Translate please The quotient of a number and the sum of the number and 5 is -2

Mathematics
1 answer:
julia-pushkina [17]4 years ago
6 0
X/X+5=-2
please mark brainiest if this helped you out<span />
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Find last year's salary, if after a 4% pay raise, this year's salary is $34,320
Oksana_A [137]
34320*100/104 = 
$33,000


4 0
3 years ago
What is the answer to this question? Please
AnnZ [28]

Answer:

y² + 8y + 16

Step-by-step explanation:

Given

(y + 4)²

= (y + 4)(y + 4)

Each term in the second parenthesis is multiplied by each term in the first parenthesis, that is

y(y + 4) + 4(y + 4) ← distribute both parenthesis

= y² + 4y + 4y + 16 ← collect like terms

= y² + 8y + 16

7 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

x^3y'' + 2x^2y' + 4y

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ;  x=x_o is  located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0

y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0

The standard form of the differential equation is :

\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0

Thus;

P(x) = \dfrac{2}{x}

Q(x) = \dfrac{4}{x^3}

The zeros of x,x^3  is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x)    and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = x*\dfrac{2}{x}

p(x) = 2

q(x) = x²Q(x)

q(x) = x^2 * \dfrac{4}{x^3}

q(x) =\dfrac{4}{x}

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic  at x = 0

Q(x) = \dfrac{4}{x^3}  do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0
3 years ago
Joe bought g gallons of gasoline for $2.65 per gallon and c cans of oil for $3.45 per can. a. What expression can be used to det
Harlamova29_29 [7]

Step-by-step explanation:

PART A

a=total amount

c=cans of oil

g=gasoline

a=2.65g+3.45c

PART B

a=2.85(8.4)+3.15(6)

a=23.94+18.90

a=42.84

Hope that helped =)

8 0
3 years ago
Geometry help needed, please :)
nasty-shy [4]

Answer:

C

Step-by-step explanation:

The Hypotenuse is y

The side opposite the given angle (60o) is 12.

You must use one of the trig functions to relate the angle, the side opposite and the hypotenuse.

It turns out that the function you need to use is the sine.

angle = 60o

Side opposite = 12 cm

hypotenuse = h = ???

Sin(60o) = opposite / hypotenuse  multiply both sides by the hypotenuse.

hypotenuse * sin(60o) = side opposite

Divide by sin(60o)

hypotenuse = side opposite / sin(60)

hypotenuse = 12/sin(60)

Sin(60) radical form = sqrt(3)/2

hypotenuse = 12 // sqrt(3)/2

hypotenuse = 24 // sqrt(3)   Rationalize the denominator.

hypotenuse = 24 * sqrt(3) // ( (sqrt(3)*sqrt(3) )

hypotenuse = 8 sqrt(3)

C

7 0
3 years ago
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