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Stells [14]
3 years ago
9

Find the percent of each number. 1. 32% of 60 =

Mathematics
2 answers:
Advocard [28]3 years ago
8 0

Answer:

Step-by-step explanation:

aivan3 [116]3 years ago
5 0

Answer:

19.2

Step-by-step explanation:

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Property for 1• (a + 3) = a +3
mina [271]

Answer: Infinitely Many Solutions

Step-by-step explanation is below.

5 0
3 years ago
Solve the following linear equation for x<br><br> 5x - 2 + x = 9 + 3x + 10
Angelina_Jolie [31]

Answer:

x = 7

Step-by-step explanation:

5x - 2 + x = 9 + 3x + 10

6x - 2 = 9 + 3x + 10

6x - 2 = 3x + 19

6x = 3x + 21

3x = 21

x = 7

4 0
2 years ago
Read 2 more answers
Initially a tank contains 10 liters of pure water. Brine of unknown (but constant) concentration of salt is flowing in at 1 lite
zhenek [66]

Answer:

Therefore the concentration of salt in the incoming brine is 1.73 g/L.

Step-by-step explanation:

Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.

Let the concentration of salt  be a gram/L

Let the amount salt in the tank at any time t be Q(t).

\frac{dQ}{dt} =\textrm {incoming rate - outgoing rate}

Incoming rate = (a g/L)×(1 L/min)

                       =a g/min

The concentration of salt in the tank at any time t is = \frac{Q(t)}{10}  g/L

Outgoing rate = (\frac{Q(t)}{10} g/L)(1 L/ min) \frac{Q(t)}{10} g/min

\frac{dQ}{dt} = a- \frac{Q(t)}{10}

\Rightarrow \frac{dQ}{10a-Q(t)} =\frac{1}{10} dt

Integrating both sides

\Rightarrow \int \frac{dQ}{10a-Q(t)} =\int\frac{1}{10} dt

\Rightarrow -log|10a-Q(t)|=\frac{1}{10} t +c        [ where c arbitrary constant]

Initial condition when t= 20 , Q(t)= 15 gram

\Rightarrow -log|10a-15|=\frac{1}{10}\times 20 +c

\Rightarrow -log|10a-15|-2=c

Therefore ,

-log|10a-Q(t)|=\frac{1}{10} t -log|10a-15|-2 .......(1)

In the starting time t=0 and Q(t)=0

Putting t=0 and Q(t)=0  in equation (1) we get

- log|10a|= -log|10a-15| -2

\Rightarrow- log|10a|+log|10a-15|= -2

\Rightarrow log|\frac{10a-15}{10a}|= -2

\Rightarrow |\frac{10a-15}{10a}|=e ^{-2}

\Rightarrow 1-\frac{15}{10a} =e^{-2}

\Rightarrow \frac{15}{10a} =1-e^{-2}

\Rightarrow \frac{3}{2a} =1-e^{-2}

\Rightarrow2a= \frac{3}{1-e^{-2}}

\Rightarrow a = 1.73

Therefore the concentration of salt in the incoming brine is 1.73 g/L

8 0
3 years ago
Type the correct answer in each box
levacccp [35]

Answer:

76589607+789607p8=2

Step-by-step explanation:

3872oed0w89p23-98937ey9tg=2

4 0
3 years ago
Help please? I need it lol
ddd [48]

Answer:

Since magnesium = 2, and potassium = 1, magnesium is greater than potassium (2 > 1).

If we assign these elements letters, m and p respectively,

M > P

6 0
3 years ago
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