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pychu [463]
3 years ago
7

Help me tell me the answers

Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0
A. X= n+17
b. x=8xP
c. n^6
d. Q x 5/8
Sergeeva-Olga [200]3 years ago
6 0
2.(a) 17n
(b) 8p
(c) n^6 (they wrote e instead of c lol)
(d) sorry idk
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Identify the oblique asymptote of f(x) = quantity x plus 4 over quantity 3 x squared plus 5 x minus 2.
faltersainse [42]
f(x) = \frac{x + 4}{3x^{2} + 5x - 2}

                     3x² + 5x - 2 = 0
                3x² + 6x - x - 2 = 0
3x(x) + 3x(2) - 1(x) - 1(2) = 0
          3x(x + 2) - 1(x + 2) = 0
                  (3x - 1)(x + 2) = 0
3x - 1 = 0       or       x + 2 = 0
    + 1 + 1                     - 2  - 2 
     3x = 1          or          x = -2
      3     3                       1     1
       x = ¹/₃         or         x = -2

      f(x) = 3x² + 5x - 2
     f(¹/₃) = 3(¹/₃)² + 5(¹/₃) - 2
     f(¹/₃) = 3(¹/₉) + 1²/₃ - 2
     f(¹/₃) = ¹/₃ - ¹/₃
     f(¹/₃) = 0
(x, f(x)) = (¹/₃, 0)

      f(x) = 3x² + 5x - 2
     f(-2) = 3(-2)² + 5(-2) - 2
     f(-2) = 3(4) - 10 - 2
     f(-2) = 12 - 12
     f(-2) = 0
(x, f(x)) = (-2, 0)

    Vertical Asymptotes: ¹/₃ or -2
Horizontal Asymptotes: 0
      Oblique Asymptote: No Asymptotes
3 0
3 years ago
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PLEASE HELPPP WILL GIVE BRAINLIEST!!!!!
irakobra [83]

Answer:

<h2>C. 9x³ − 11x² − 7x </h2>

Step-by-step explanation:

f(x)=36x^5-44x^4-28x^3\\\\g(x)=4x^2\\\\\dfrac{f(x)}{g(x)}=\dfrac{36x^5-44x^4-28x^3}{4x^2}\\\\\dfrac{f(x)}{g(x)}=\dfrac{(4x^2)(9x^3)-(4x^2)(11x^2)-(4x^2)(7x)}{4x^2}\\\\\dfrac{f(x)}{g(x)}=\dfrac{(4x^2)(9x^3-11x^2-7x)}{4x^2}\qquad\text{cancel}\ 4x^2\\\\\dfrac{f(x)}{g(x)}=9x^3-11x^2-7x

7 0
2 years ago
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What is the answer to 5(6p+5)
AfilCa [17]

Answer:

30p + 25

Step-by-step explanation:

I hope this helps.

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Write an equation in slope-intercept form of the line with slope −4/5 that contains the point (−5,−4).
Dmitry [639]

Answer:

B

Step-by-step explanation:

<u>Slope-intercept form:</u>

y= mx +c, where m is the slope and c is the y-intercept.

Given that the slope is -4/5,

y =  -  \frac{4}{5} x + c

To find the y-intercept, substitute a pair of coordinates.

When x= -5, y= -4,

- 4 =  -  \frac{4}{5} ( - 5) + c \\  - 4 =  4 + c \\ c =  - 4  -  4 \\ c =  - 8

Thus, the equation of the line is

y =  -  \frac{4}{5} x - 8

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The mean doesn't have outliers, and if you're looking for a perfect middle of your data, the median is the best.

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