Answer:
The requirements for the hypothesis test does satisfied the method for testing the claim that from two population proportions the rate of polio is less for children given the salk vaccine.
Step-by-step explanation:
The percentage of children in the treatment group was:
(201229/401974)*100 = 49.9%
The percentage of children given placebo was:
(200745/401974)*100 = 50.1%
The percentage of children that developed polio in the treatment group:
(33/200745)*100 = 0.0164%
The percentage of children that developed polio in the placebo group:
(115/201229)*100 = 0.0571%
The percentage difference between the two group:
((0.0571-0.0164)/0.0571) = 61.62%
Therefore:
The amount of children used for each group was almost divided into half of the total amount of children. The test revealed although very small percentages of the both group developed polio, 68.62% more children given placebo than the children that was given the salk vaccine. Therefore, the study shows that the rate of polio is less for children given the salk vaccine and the the hypthesis test is satisfied.
Answer:
ewfyeet
Step-by-step explanation:
Answer:
And rounded up we have that n=20545
Step-by-step explanation:
Assuming this question: Use the data to find minium sample size required to estimate population proportion. Margin of error: 0.009, confidence level: 99%, p and q are unknown.
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by
and
. And the critical value would be given by:
The margin of error for the proportion interval is given by this formula:
(a)
And on this case we have that
and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
Assuming an estimation of p as
. And replacing into equation (b) the values from part a we got:
And rounded up we have that n=20545
A is the answer. 204/4 is 51, 306/6 is 51,etc. The car travels 51 miles every 1 hour.
Answer:
18 m/s
Step-by-step explanation:
We used the given expression for the wind power:
replacing the power (on the left hand side of the equal sign) by 15.83 MegaWatts, and then solve for v which is raised to the power 3:
![P(v)=0.002713v^3\\15.83=0.002713v^3\\\frac{15.83}{0.002713} =v^3\\v^3=5834.87\\v=\sqrt[3]{5834.87} =18.003\frac{m}{s}](https://tex.z-dn.net/?f=P%28v%29%3D0.002713v%5E3%5C%5C15.83%3D0.002713v%5E3%5C%5C%5Cfrac%7B15.83%7D%7B0.002713%7D%20%3Dv%5E3%5C%5Cv%5E3%3D5834.87%5C%5Cv%3D%5Csqrt%5B3%5D%7B5834.87%7D%20%3D18.003%5Cfrac%7Bm%7D%7Bs%7D)