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2 years ago

Find the product of (3x - 2)and(6x + 1)

Mathematics

2 answers:

Lapatulllka [165]2 years ago

4 0

Answer:

18x² - 9x - 2

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

3x(6x + 1) - 2(6x + 1) ← distribute both parenthesis

= 18x² + 3x - 12x - 2 ← collect like terms

= 18x² - 9x - 2

stealth61 [152]2 years ago

3 0

Use foil (first, outer, inner, last)

First terms: 3x * 6x = 18x²

Outer terms: 3x * 1 = 3x

Inner terms: -2 * 6x = -12x

Last terms: -2 * 1 = -2

Put all that together to get 18x² + 3x - 12x - 2

3x and -12x can be combined because they're like terms; 3x - 12x = -9x

So the final product is 18x² - 9x - 2

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456 divided by n=4.56

Arlecino [84]

To find this out, just divide 456, by the answer of 4.56
So once you divide that, you get 100.
So, n=100
CHECK:
456 divided by 100=4.56
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Hope this helped :)

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2 years ago

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3 years ago

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A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%

Mamont248 [21]

Answer:

a. $A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\$

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Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

$A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\$

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

$\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}$

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