Show that if the first 10 positive integers 1,2,3,···,10 are placed around a circle, in any order,there exists three integers in
consecutive locations around the circle that have a sum greater thanor equal to 17. Is your proof constructive or non-constructive ?
1 answer:
Answer:
Let A1=a1+a2+a3, A2=a2+a3+a4, and so on, A10=a10+a1+a2. Then A1+A2+⋯+A10=3(a1+a2+⋯+a10)=(3)(55)=165, so some Ai≥165/10=16.5, so some Ai≥17.
Step-by-step explanation:
You might be interested in
Answer:
biased
Step-by-step explanation:
Answer:
So you would not be carried away by the tides
Step-by-step explanation:
hope this is what u want
Answer:
Step-by-step explanation:(4+7)-(1)
That's false.
Let's see an instance:
10% of 300=30
20% of 100=20
It doesn't work here so it's false