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lys-0071 [83]
3 years ago
8

Show that if the first 10 positive integers 1,2,3,···,10 are placed around a circle, in any order,there exists three integers in

consecutive locations around the circle that have a sum greater thanor equal to 17. Is your proof constructive or non-constructive ?
Mathematics
1 answer:
zysi [14]3 years ago
7 0

Answer:

Let A1=a1+a2+a3, A2=a2+a3+a4, and so on, A10=a10+a1+a2. Then A1+A2+⋯+A10=3(a1+a2+⋯+a10)=(3)(55)=165, so some Ai≥165/10=16.5, so some Ai≥17.

Step-by-step explanation:

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A=340
ASHA 777 [7]

Answer:

  16666.25

Step-by-step explanation:

For rounded values, the minimum value they could have been rounded from is the given value less half its least-significant digit.

That means the minimums are ...

  a: 340 ⇒ 340 -5 = 335

  b: 49.8 ⇒ 49.8 -0.05 = 49.75

Then the minimum product would be ...

  (335) × (49.75) = 16666.25

8 0
1 year ago
What is the solution for a2 -b2
Sphinxa [80]
2(a-b)

this is the answers
4 0
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denpristay [2]

Answer:

V = 314.2 ft^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h    r is the radius (5) and h is the height (4)

Using the pi button for pi

V = pi (5^2) (4)

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Rounding to the nearest tenth

V = 314.2 ft^3

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3 years ago
Rational numbers that are not integers and whole numbers that aren't integers.
Nataly [62]
Whole number can be a integer. rational number can not  be  a integer that is  repeating.
8 0
3 years ago
Sean is helping his dad build a tiled walkway in their backyard. The walkway will be 69 feet long and 2 feet wide. The local har
Flura [38]
First we should figure out how many times 2 goes into 69,(because each tile is 2 feet long) and I am going to do that by dividing 69 by 2. I got 34.5, so we can just say 35 to make it easier. So we now know we need 35 tiles, but they come in boxes of 6, so we will need to divide 35 by 6. It didn't make a full number (it was 5.833) but we need a full number of tiles so we will round up.

Our final number of how many boxes of tiles is 6.
6 0
2 years ago
Read 2 more answers
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