You have to line them up for example 1 is in a straight line and so is 3 and 5 you can choose between 3 and five but what about the middle 4.
Answer:
The ratio of the intensities is roughly 6:1.
Step-by-step explanation:
The intensity I() of an earthquake wave is given by:
<em>where P: is the power ans d: is the distance. </em>
Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km </em>

Therefore, the ratio of the intensities is roughly 6:1.
I hope it helps you!
Answer: V = (10.4 mph, 38.6 mph)
Step-by-step explanation:
The velocity is written as (vx, vy)
where vx is the component of the velocity in the x-axis and vy is the component of the velocity in the y-axis.
In usual notation, the angles are measured counterclockwise from the positive x-axis.
We know that the angle is 75°, this means that the velocity in the x-axis will be equal to the total velocity of the bird projected in the x-axis (suppose a triangle rectangle, where the velocity is the hypotenuse, the x component is a cathetus and the y component is other cathetus)
vx = 40mph*cos(75°) = 10.4 mph
vy = 40mph*sin(75°) = 38.6mph
Then the vector of velocity is V = (10.4 mph, 38.6 mph)
Answer:

Step-by-step explanation:





