Answer:
15 marker's
Step-by-step explanation:
37+24=61
61÷4=15.25
because she wants an even number of makers the answer is 15.
Answer:
following are the solution to this question:
Step-by-step explanation:
please find the given table in the attached file.
Its circulatory system point-slope type involves picking out the formula for two points. That marker shape is:

In measure the slope m, we will use both levels. Or get one of the levels of teleport plugged in for
(both do not matter)
Phase 1: I can choose two points from a list for a calculation of m slope: (1, 22) and (3, 46)
The m slope =12
Phase 2: going to settle on one of the plug-in points for
:
I get: y - 22 = 12 (x - 1) formulas 1 of
If you choose to answer throughout the form of the a slope instead of a point slope form, you must modify Equation 1 to come in the form of a slope intercept.
4/5x=7/5 you have to divide 7/5 by 4/5 which equals to 1.75/5 which is equal to x
Answer:
<em><u>9</u></em><em><u>0</u></em><em><u>. </u></em><em><u>(</u></em><em><u> </u></em><em><u>was </u></em><em><u>the </u></em><em><u>full </u></em><em><u>capacity</u></em><em><u> of</u></em><em><u> </u></em><em><u>jug</u></em><em><u>)</u></em>
<em><u>to </u></em><em><u>solve </u></em><em><u>this</u></em><em><u> </u></em>
<em><u>firstly</u></em><em><u> </u></em><em><u>let </u></em><em><u>the </u></em><em><u>full </u></em><em><u>capacity</u></em><em><u> </u></em><em><u>of </u></em><em><u>jug </u></em><em><u> </u></em>
<em><u> </u></em><em><u> </u></em>
<em><u>be</u></em><em><u>. </u></em><em><u>x</u></em>
<em><u>so,</u></em><em><u> </u></em>
<em><u>4</u></em><em><u>/</u></em><em><u>5</u></em><em><u>*</u></em><em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u>2</u></em>
<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u>2</u></em><em><u>*</u></em><em><u>5</u></em><em><u>/</u></em><em><u>4</u></em>
<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>9</u></em><em><u>0</u></em>
<em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em>