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3 years ago

Code the function definition for aNonclassFunction, picking up co. aNonclassFunction has no return value.

Computers and Technology

1 answer:

enot [183]3 years ago

6 0

Answer:

b)void aNonclassFunction (Banana co);

Explanation:

In the function definition you have to pass the tell the function which type of argument it is taking.In our case we are taking a variable co of Banana type passing it to the function named aNonclassFunction having no return type.

So the definition will be like this.

void aNonclassFunction (Banana co);

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1) What is Database? List its Uses.

Serggg [28]

Answer:

a database stores a large sum of data

Explanation:

its used to keep track of things like student names bank accounts and other things

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2 years ago

In python please:

Vikki [24]

Answer:

if 'marsupial' in dictionary:

del dictionary['marsupial']

else:

print("The key marsupial is not in the dictionary")

Explanation:

So you can use the keyword "in" to check if a certain key exists.

So the following code:

if key in object:

# some code

will only run if the value of "key" is a key in the object dictionary.

So using this, we can check if the string "marsupial' exists in the dictionary.

if 'marsupial' in dictionary:

# code

Since you never gave the variable name for the variable that references a dictionary, I'm just going to use the variable name "dictionary"

Anyways, to delete a key, there are two methods.

del dictionary[key]

dictionary.pop(key)

Both will raise the error "KeyError" if the key doesn't exist in the dictionary, although there is method with pop that causes an error to not be raised, but that isn[t necessary in this case, since you're using the if statement to check if it's in the dictionary first.

So I'll just use del dictionary[key] method here

if 'marsupial' in dictionary:

del dictionary['marsupial']

else:

print("The key marsupial is not in the dictionary")

The last part which I just added in the code is just an else statement which will only run if the key 'marsupial' is not in the dictionary.

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2 years ago

It is okay to use a dust rag when cleaning the inside of a computer.

Sunny_sXe [5.5K]

Yes you can do that, it won't hurt the computer.

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3 years ago

Read 2 more answers

Develop a C program that calculates the final score and the average score for a student from his/her (1)class participation, (2)

Ghella [55]

Answer:

#include <iomanip>

#include<iostream>

using namespace std;

int main(){

char name[100];

float classp, test, assgn, exam, prctscore,ave;

cout<<"Student Name: ";

cin.getline(name,100);

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){ cout<<"Class Participation: "; cin>>classp; }

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){ cout<<"Test: "; cin>>test; }

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){ cout<<"Assignment: "; cin>>assgn; }

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){ cout<<"Examination: "; cin>>exam; }

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){ cout<<"Practice Score: "; cin>>prctscore; }

ave = (int)(classp + test + assgn + exam + prctscore)/5;

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;

return 0;}

Explanation:

The required parameters such as cin, cout, etc. implies that the program is to be written in C++ (not C).

So, I answered the program using C++.

Line by line explanation is as follows;

This declares name as character of maximum size of 100 characters

char name[100];

This declares the grading items as float

float classp, test, assgn, exam, prctscore,ave;

This prompts the user for student name

cout<<"Student Name: ";

This gets the student name using getline

cin.getline(name,100);

This prompts the user for class participation. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){ cout<<"Class Participation: "; cin>>classp; }

This prompts the user for test. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){ cout<<"Test: "; cin>>test; }

This prompts the user for assignment. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){ cout<<"Assignment: "; cin>>assgn; }

This prompts the user for examination. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){ cout<<"Examination: "; cin>>exam; }

This prompts the user for practice score. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){ cout<<"Practice Score: "; cin>>prctscore; }

This calculates the average of the grading items

ave = (int)(classp + test + assgn + exam + prctscore)/5;

This prints the calculated average

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;

8 0

3 years ago

Leah’s computer is connected to the network most of the time. Once, she noticed few of her files with sensitive data were missin

vivado [14]

Answer:

The Firewall (Router) is the vulnerable hardware.

Explanation:

The entry into the network will be the firewall (If there is a firewall installed on the network), if this medium is compromised, every workstation on the network will be vulnerable.

3 0

3 years ago