1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
Answer:
The error interval for x is:
[3.65,3.74]
Step-by-step explanation:
The number after rounding off is obtained as:
3.7
We know that any of the number below on rounding off the number to the first decimal place will result in 3.7:
3.65 3.66 3.67 3.68 3.69 3.70 3.71 3.72 3.73 3.74
( Because if we have to round off a number present in decimals to n place then if there is a number greater than or equal to 5 at n+1 place then it will result to the one higher digit at nth place on rounding off and won't change the digit if it less than 5 )
Hence, the error interval is:
[3.65,3.74]
Answer: 14
Step-by-step explanation:
Given
Excavation cone measures
height 
Diameter 
Truck can dump 
at a time
The volume of a cone is
Putting values
No of trips(N) required to accumulate this much volume is given by
Therefore, 14 trips are necessary to accumulate a cone of volume 
Answer:
x= no solution
Step-by-step explanation:
4x-2+x=-2+2x
We first add 4x+x on the left side.
5x-2=2+2x
We then add 2 to both sides.
5x=2x
The answer is no solution because we got no answer out of the equation.
