The answer is 4, the equation for that and to get that answer would be 32 divided by 8
This is your answer, hope this helps :D !
Answer:
perpendicular line through a point on a line
Step-by-step explanation:
The circle centered at C seems intended to produce point D at the same distance as point B. That is, C is the midpoint of BD.
The circles centered at B and D with radius greater than BC seems intended to produce intersection points G and H. (It appears accidental that those points are also on circle C. As a rule, that would be difficult to do in one pass.)
So. points G and H are both equidistant from points B and D. A line between them will intersect point C at right angles to AB.
Segment GH is perpendicular to AB through point C (on AB).
![2\sqrt8\times8\sqrt2=(2\times8)\sqrt{8\times2}=16\sqrt{16}=16\times4=64](https://tex.z-dn.net/?f=2%5Csqrt8%5Ctimes8%5Csqrt2%3D%282%5Ctimes8%29%5Csqrt%7B8%5Ctimes2%7D%3D16%5Csqrt%7B16%7D%3D16%5Ctimes4%3D64)
Alternatively, you can write radicals as rational exponents, so that you get
![2\sqrt8\times8\sqrt2=2\tiems8^{1/2}\times8\times2^{1/2}=2^{3/2}8^{3/2}](https://tex.z-dn.net/?f=2%5Csqrt8%5Ctimes8%5Csqrt2%3D2%5Ctiems8%5E%7B1%2F2%7D%5Ctimes8%5Ctimes2%5E%7B1%2F2%7D%3D2%5E%7B3%2F2%7D8%5E%7B3%2F2%7D)
Then recalling that
![2^3=8](https://tex.z-dn.net/?f=2%5E3%3D8)
, you have