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3 years ago

15

6.4−2.4÷0.1= what (Enter your answer in as a decimal please.)

1 answer:

mamaluj [8]3 years ago

3 0

The answer would be -17.6.

Simplify 2.4 divided by 0.1 to 24 ( 6.4 - 24 )

Simplify ( -17.6 ).

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What is angle A equal? <br><br> Thanks :)

Alex Ar [27]

Angle A and angle B sums up to 180 (interior angles)

6x - 35 + 3x + 53 = 180
9x + 18 = 180
9x = 162
x = 18

angle A = 6(18)-35 = 73 degrees

7 0

2 years ago

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How to expand and simplify this equation 7(2a+3)+3(4a-2).

Pavel [41]

Ok, so first we distribute, you multiply the seven into everything in the parentheses next to it. So far we have, 14a+21+3(4a-2). You distribute the three into the parentheses to get, 14a+21+12a-6. You combine the like terms to get, 26a-15. You cannot simplify it any further so the answer is 26a-15.

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3 years ago

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Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

2 years ago

5-(n-4)=3(n+2)<br> Please help I’ll give brainliest

DedPeter [7]

If your salving for n it would be n=0.75
If your salving by factoring it is 3/4

4 0

2 years ago

Can the expression be used to solve 29x14? yes or no for each expression a(9x4)+(20x4)+(9x1)+(20x1) yes No

Alekssandra [29.7K]

no because

29×14 is 406

9×4

20×4

9×1

<u>20×1</u>

49×10 490

490 and 406 aren't equal

7 0

3 years ago