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AlexFokin [52]
3 years ago
5

Write the equation of the line that passes through the points (3, 6) and (5, 18) using function notation.

Mathematics
2 answers:
faust18 [17]3 years ago
6 0

The answer would be B: F(x) = 6x - 12

This line passes through both given points.

mylen [45]3 years ago
6 0

First, we must find the slope using the equation

\frac{y_{2}-y_{1} } {x_{2}-x_{1}}

We can substitute in our points and will get

\frac{18-6}{5-3} =\frac{12}{2} = 6

This means that our slope is m=6.

We can now use the point slope form to find the equation of the line. The equation for this is y-y_{1} =m(x-x_{1})

Now we can substitute in one of our point, (3,6) in this case.

y-6 = 6(x-3)

this simplifies to

y= 6x-12

now we can swap y for f(x) to put it in function notation

this means that the answer is f(x) = 6x-12; which means that the answer is b

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A cyclist travels at distance of 400 meters in 120 seconds towards school, calculate his speed. (Show your work)
DochEvi [55]

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

Speed=\frac{distance}{time}

in this problem we have

distance=400\ m \\time=120\ sec

substitute in the formula

Speed=\frac{400}{120}

Speed=3.5\frac{m}{sec}

therefore

<u>the answer Part a) is</u>

the speed is equal to 3.5\frac{m}{sec}

<u>Part b) </u>Find the velocity

we know that

<u>Velocity </u>is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

magnitude=3.5\frac{m}{sec}

direction=North\ East\ (NE)

therefore

<u>the answer Part b) is</u>

the velocity is 3.5\frac{m}{sec}\ North\ East\ (NE)

Part c)

we know that

the acceleration is equal to the formula

a=\frac{V2-V1}{t2-t1}

in this problem we have

V2=0 \\V1=3.5\frac{m}{sec}

t2=15\ sec\\t1=0

substitute in the formula

a=\frac{0-3.5}{15-0}

a=-\frac{3.5}{15}\frac{m}{sec^{2}}

a=-\frac{7}{30}\frac{m}{sec^{2}}

therefore

<u>the answer Part c) is</u>

the acceleration is -\frac{7}{30}\frac{m}{sec^{2}}

This is an example of negative acceleration

7 0
3 years ago
Read 2 more answers
Evaluate p2m−(np+r) if m=−32 , n=2 , p=−8 , and r=4
harkovskaia [24]
When you evaluate the equation you plug in the numbers or replace the variables with the numbers it’s giving you.
-8(2)(-32) - 2(-8) + 4
-16(-32) - 16 + 4
512 + 20
= 532
Hope this helps!
8 0
3 years ago
(FOR K-12 STUDENTS) Keith correctly determined the area of this parallelogram by adding the areas of the triangles and rectangle
Gemiola [76]

The area of the parallelogram using area of rectangle and area of two triangles is 84 m²

<h3>How to find area of a parallelogram</h3>

  • Area of a rectangle = length × width

= 8m × 7m

= 56 m²

  • Area of each triangle = 1/2 × base × height

= 1/2 × 4m × 7m

= 1/2 × 28

= 14m²

  • Total area of triangles = 2(14 m²)

= 28 m²

  • Area of parallelogram = area of rectangle + area of two triangles

= 56 m² + 28 m²

= 84 m²

Learn more about area of triangle:

brainly.com/question/21735282

4 0
2 years ago
Read 2 more answers
What is the value for x?
schepotkina [342]
Right of the bat, I know the measure of angle C equals 73° because of the Isosceles Base Angle Theorem. Then, due to the Triangle Sum Theorem, I know that all of the measures in the triangle must add to 180°. To find this, just subtract 73 and 73 from 180. Finally, because angle B equals (6x + 4) and 34°, just set them equal to each other to find the value of x.


180 - 73 - 73 = measure of angle B
34° = measure of angle B

6x + 4 = 34
      - 4    - 4
6x = 30
6x / 6 = 30 / 6
x = 5

Hope this helps!
3 0
3 years ago
Jonathan must determine the solutions of the quadratic equation
irinina [24]

Answer:The answer is C

Step-by-step explanation:

5 0
3 years ago
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