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Alexxandr [17]
3 years ago
13

At a parade, 1/4 of the participants have red hair, 1/6 of them have brown hair, and the rest of the participants have black hai

r. What fraction of the participants have black hair?
Mathematics
1 answer:
Orlov [11]3 years ago
6 0
Add 1/4 by 1/6 and get 5/12 so then you have 7/12 with black hair.
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1.07, 1.7 and 1.007 in order from<br><br>greatest to least​
Vladimir [108]
1.7 , 1.07 , 1.007 greatest to least
4 0
3 years ago
A small juice company spends $1200 per day on business expenses plus $1.10 per bottle of juice them make. They charge $2.50 for
Greeley [361]
Cost price per bottle of juice = $1.10 
Selling price per bottle of juice = $2.50 
Profit per bottle of juice = $2.50 - $1.10 = $ 1.40 
Let B be the number of bottles needed to sell in one day in order to equal its daily costs. 
$1200 = $1.40B 
857.14285714285714 = B 
858 = B (round off to the nearest bottle) 

The company must sell 858 bottles of juice in one day in order to equal its daily cost. 

Hope this helps! =)


5 0
3 years ago
What is the Circumference of a circle with a radius of 5? Use 3.14 for pi
Thepotemich [5.8K]

Answer:

=78.5cm

Step-by-step explanation:

pi=3.14

formula=3.14×r×r

3.14×5×5

78.5

4 0
2 years ago
Please try and help me with this question I need help
Umnica [9.8K]
B) an=5^n−1
d) an=10^n−1
8 0
3 years ago
The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
BabaBlast [244]

Step-by-step explanation:

the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).

I think your teacher made a mistake, or you made one when typing the question in here.

there is no factor r that creates

15×r = 9

and

9×r = 5/27

it would mean that

15 × r² = 5/27

r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81

r = 1/9

but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9

and 9 × 1/9 = 9/9 = 1 is NOT 5/27

so, this can't be right.

on the other hand

15 × r = 9

r = 9/15 = 3/5

and then

9 × 3/5 = 27/5

so, either the sequence should have been

15, 5/3, 5/27

or (and I suspect this to be true)

15, 9, 27/5

under that assumption we have

s1 = 15

r = 3/5

sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)

s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =

= 3 × 19683/390625 = 59049/390625 =

= 0.15116544 ≈ 0.151

6 0
2 years ago
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