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emmasim [6.3K]
3 years ago
6

You need to create a chart showing the past year sales results for the university bookstore. Your chart will show the total sale

s by month for twelve months. Which of the following is the best chart type? Question 1 options: A) pie chart B) line chart C) scatter chart D) either line or column chart
Mathematics
1 answer:
EleoNora [17]3 years ago
6 0

Answer:

D) either line or column chart

Step-by-step explanation:

Line or column charts are better used to show changes of a value over a period of time. Its visually easy to compare changes between the months in a column chart. A line chart its usually used to compare the data over time of several groups.

A Pie chart is better used when you want to compare a part of the data to a whole.

A Scatter chart it is best to compare two variables X and Y, and see their relations.

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Answer: option 1.

log_{4} x

x      f(x)

4      log (4) 4 = 1 ... because 4^1 = 4

16    log(4) 16 = 2 .... because 4^2 = 16

64    log (4) 64 = 3 .... because 4^3 = 64


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Solve for x. 3x+1=7 What is the root? If there is no root, choose none.
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I think the root of "3x + 1 = 7" is 2...

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A rectangular prism with a length of 14 meters, width of 5 meters, and height of 4.5 meters. A square pyramid with a base of 8 f
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B. Mecca's leaders forced Muhammad to leave the city.

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7. A number of minor automobile accidents occur at various high-risk intersections in Teton County despite traffic lights. The T
Anit [1.1K]

Answer:

Modification has not reduced the number of accidents.

Step-by-step explanation:

H_0: \mu\geq0\\H_a:\mu

                                 A  B  C   D   E   F  G   H

Before modification 5  7  6   4    8   9   8   10

After modification    3  7  7   0    4   6   8    2

Difference                -2 0  1   -4   -4   -3  0   -8

Mean of differences M_d = \frac{sum}{8}=\frac{2+0-1+4+4+3-0+8}{8}=2.5

Standard deviation of differences = \sqrt{\frac{\sum(x-\bar{x})^2}{n}}=2.9277

Formula of paired t test :

t=\frac{M_d}{\frac{s}{\sqrt{n}}}\\t=\frac{2.5}{\frac{2.9277}{\sqrt{8}}}\\t = 2.4152

Df = n-1 = 8-1 =7

t critical = t_{(df, \alpha)}=t_{7,0.01}=2.998

t critical> t calculated

So, We failed to reject null hypothesis

Hence modification has not reduced the number of accidents.

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