Can someone help me with this math? Please I'm desperate.
1 answer:
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Answer:
The expected value of the winnings for a single-ticket purchase is -$1.0016.
Step-by-step explanation:
The total number of tickets sold is, <em>N</em> = 1250.
Cost of one ticket is, $4.
Let <em>X</em> = amount of prize.
The prize distribution is as follows:
1 Grand price = $3000
1 Second prize = $450
10 Third prize = $25
The expected value <em>X</em> can be computed using the formula:
Compute the probability distribution of <em>X</em> as follows:
Prize Amount (X) P (X) x · P (X)
1 Grand prize $3000
1 Second prize $450
10 Third prize $25
No prize -$4
TOTAL 1.0000 -1.0016
Thus, the expected value of the winnings for a single-ticket purchase is -$1.0016.
Answer:
x = - , x = 2
Step-by-step explanation:
To find h(g(x)) substitute x = g(x) into h(x) , that is
h(g(x))
= h(x + 1)
= (x + 1)²
= x² + 2x + 1
For h(g(x)) = 3x² + x - 5 , then
3x² + x - 5 = x² + 2x + 1 ← subtract x² + 2x + 1 from both sides
2x² - x - 6 = 0 ← in standard form
(2x + 3)(x - 2) = 0 ← in factored form
Equate each factor to zero and solve for x
2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = -
x - 2 = 0 ⇒ x = 2