Answer:
16.36%
dependent
Step-by-step explanation:
If we choose a crayon, then another crayon without putting the first one back in the supplies box, that means the event is dependent. The keyword to find whether some events dependent is " without putting back" because that means the first pick will reduce the number of crayons pool for the second pick.
There are 3 + 2 + 6 = 11 total crayons. There are 6 blue and 3 red crayons. The probability for picking blue then red crayon will be:
6/11 * 3/10 = 18/110= 0.163636 = 16.36%
Answer:
1.) It is biased
2.) No
3.) Yes
4.) No
Step-by-step explanation:
1.) It is biased as it is predisposition to one particular outcome over another.
2.) No, because biased in research leads to unrepresentative outcomes as the estimates is predisposed to the left or to the right of the true values.
3.) Yes. Since the selection of shift has an equal probability of being chosen.
4.) No. The probability that the sample accurately reflects the efficiency of the workers, the standard should be 95%.
Answer:
-6m^2 *n^2
Step-by-step explanation:
formula: (m^x)/(m^y)= m^(x-y)
apply formula for (4m^2)/(2m^-3)
=(4m^(2--3)/(2)
=4m^5/2
divide 4/2
=2m^5
next part 3n^5/(-mn)^3
3n^5/(-mn)^3
expand
=3n^5/ (-m^3*n^3)
=3n^(5-3)/ -m^3
=3n^2/ -m^3
both parts:
(2m^5* 3n^2)/ -m^3
= -(2m^5* 3n^2)/ m^3
= -(2m^(5-3)* 3n^2)/ 1
= -(2m^2* 3n^2)
= -(6m^2*n^2)
= -6m^2 *n^2
Answer:
B
Step-by-step explanation:
3 8/9 - 1/3
1/3=3/9
3 8/9 - 3/9= 3 5/9
