Each sector shown has an equal area.

Mathematics

1 answer:

valentina_108 [34]3 years ago

7 0

Answer:

I think it is 40% (Not sure)

Step-by-step explanation:

First, you want to find out how much percent is in one square. To find that out you divide 5 by 100 because 100 is basically 1 in this situation. 100/5 is equal to 20% so that means any one part (Shaded or not) is 20%. Then add the shaded squared up and you get 40%.

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3^3/3^6 a. 1/27 b 1/9 c 9 d -27 I think the answer is c

STatiana [176]

Answer:

a. 1/27

Step-by-step explanation:

When dividing exponents and the base is the same, we subtract them

x^a/ x^b = x^(a-b)

3^3/3^6

3^(3-6)

3^(-3)

The negative exponent means it is in the denominator

1/3^3

1/27

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B12x%7D%7B2x-3x-10%7D%20-%20%5Cfrac%7Bx%7D%7B%28x-5%29%7D" id="TexFormula1" title="\f

uysha [10]

Answer:

Step-by-step explanation:

$\frac{12x}{2x-3x-10}-\frac{x}{x-5}=\frac{12x}{-x-10}-\frac{x}{x-5}\\\\=\frac{12x}{-(x+10)}-\frac{x}{x-5}\\\\=\frac{-12x}{x+10}-\frac{x}{x-5}\\\\=\frac{-12x*(x-5)}{(x+10)*(x-5)}-\frac{x*(x+10)}{(x-5(x+10)}\\\\=\frac{-12x*x-5*(-12x)}{(x+10)(x-5)}-\frac{x*x+x*10}{(x-5)(x+10)}\\\\=\frac{-12x^{2}+60x}{(x+10)(x-5)}-\frac{x^{2}+10x}{(x-5)(x+10)}\\\\=\frac{-12x^{2}+60x-(x^{2}+10x)}{(x+10)(x-5)}\\\\=\frac{-12x^{2} + 60x - x^{2}-10x}{x^{2}+5x-50}\\\\=\frac{-13x^{2}+50x}{x^{2}+5x-50}$