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Alexxandr [17]
3 years ago
13

How could two data sets could have the same means and modes but still differ greatly? Give an example with two data sets to illu

strate.
Mathematics
1 answer:
wariber [46]3 years ago
4 0
The sets would have different sizes and standard deviations. Examples will vary. A general method for constructing
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A flowerpot has a circular base with a diameter of 27 centimeters. Find the circumference of the base of the flowerpot. Round to
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Answer:

84.82cm :}

Step-by-step explanation:

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3 years ago
No links need help ASAP
Alexandra [31]

Answer:

4, 2

Step-by-step explanation:

The formulas for 180 clockwise and counterclockwise wise is -x,-y since both of them are negative they would become positive because -x * -x = + same with y.

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3 years ago
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the ratio of boys to girls at the beach cleanup was 7:8. If there were 43 boys, how many girls were there?
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I'm pretty sure there were 48 girls at the beach clean up. 43 ÷ 7 = 6.14 (6 cause there's not gonna be floating males with missing body parts). So we multiply 6 x 8 and we get 48.
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3 years ago
PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK​
Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = ∠KLM
  • A = LN = 8
  • H = KL = 15.2

\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

6 0
2 years ago
A randomly generated list of integers from 0 to 4 is being used to simulate an event, with the numbers 1, 2, and 3 representing
Tresset [83]

Answer:

I think the anwser is

<h2>C.60 percent</h2>

hope it helped

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