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Alexxandr [17]
3 years ago
13

How could two data sets could have the same means and modes but still differ greatly? Give an example with two data sets to illu

strate.
Mathematics
1 answer:
wariber [46]3 years ago
4 0
The sets would have different sizes and standard deviations. Examples will vary. A general method for constructing
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Pls help me very urgently needed
Kisachek [45]
Ratio is 7:9
add the ratio it becomes 16
272 members divided by 16
that makes it 17 per one ratio
women ratio is 9
17x9 is 153
i=153 women in the sports club

same thing with ii except it’s divided by 7
91/7 is 13
which means 13 per ratio
there are 9 ratios of women
9x13=117
ii=117 women in a sports club with 91 men with a ratio of 7:9
4 0
3 years ago
a particular species of bamboo can grow up to 91 centimeters in a day. how fast is this in inches per hour
solniwko [45]
I would probably just do 91 times 60 since 60 min is 1 hour
8 0
3 years ago
a railroad track rises 30feet for every 400 feet of track. what is the measure of the angle of elevation of the track?
tensa zangetsu [6.8K]
It will be 0.075 the tracks
4 0
4 years ago
Read 2 more answers
The base of a regular pyramid is a hexagon. The figure shows a regular hexagon with center C. An apothem is shown as a dashed se
tatuchka [14]
Answer: 294√3

Explanation:


1) The described hexagon has these featrues:
a) 6 congruent equilateral triangles whose side lengths measure 14
b) height of each triangle = apotema = a
c) the area of each triangle is base × a / 2 = 14 × a / 2 = 7a


2) a is one leg of a right triangle whose other leg is 14 / 2 = 7, and the hypotenuse is 14.

3) Then you can use Pythagorean theorem fo find a:

14² = 7² + a² ⇒ a² = 14² - 7² = 147 ⇒ a = √ 147 = 7√3

4) Therefore, the area of one triangle is: 14 × 7√3  / 2 = 49√3

5) And the area of the hexagon is 6 times that: 6 × 49√3 = 294√3
8 0
3 years ago
If x²-5x +1 =0, what is the value of -<br><img src="https://tex.z-dn.net/?f=%28x%20%2B%20%20%5Cfrac%7B1%7D%7Bx%7D%20%29%20%20" i
ra1l [238]
<h3>Answer:   5</h3>

=================================================

Work Shown:

x^2 - 5x + 1 = 0

x^2 + 1 - 5x = 0

x^2 + 1 = 5x

(x^2 + 1)/x = 5    .... where x is nonzero

(x^2)/x + (1/x) = 5

x + (1/x) = 5

---------------

An alternative method involves solving the original equation using the quadratic formula. After you get the two roots x = p and x = q, you should be able to find that p + 1/p = 5 and also q + 1/q = 5 as well.

In this case,

p = (5 + sqrt(21))/2

q = (5 - sqrt(21))/2

8 0
3 years ago
Read 2 more answers
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