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Verdich [7]
3 years ago
14

I am really bad at math. What is AC?

Mathematics
2 answers:
kotykmax [81]3 years ago
4 0
The line from a to c
ycow [4]3 years ago
4 0
Triangle CBG is a right triangle
GB= GE = GD = 9
CD = 32
so
GC = 32 + 9 = 41

BC = √(41^2 - 9^2)
BC = √(1681 - 81)
BC = √1600
BC = 40

AB = FE = 29
So AC = 29 + 40
AC = 69

answer
AC = 69

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Find the<br> -2<br> -4<br> -3<br> -1<br> -9-8<br> determinant OF<br> -15<br> - 5<br> 6
sesenic [268]

Determinants are defined only for square matrices, so I assume you are given the 3×3 matrix

A = \begin{bmatrix}-2 & -4 & -3 \\ -1 & -9 & -8 \\ -15 & -5 & 6 \end{bmatrix}

Let's compute the determinant by taking the cofactor expansion along the first column:

\det A = -2 \det\begin{bmatrix}-9 & -8 \\ -5 & 6\end{bmatrix} + \det\begin{bmatrix}-4 & -3 \\ -5 & 6\end{bmatrix} - 15 \det \begin{bmatrix}-4 & -3 \\ -9 & -8\end{bmatrix}

\det A = -2 ((-9)\times6-(-8)\times(-5)) + ((-4)\times6 - (-3)\times(-5)) \\ ~~~~~~~~~~~~~~~- 15 ((-4)\times(-8)-(-3)\times(-9))

\det A = -2(-54-40) + (-24 - 15) - 15 (32 - 27)

\det A = \boxed{74}

5 0
2 years ago
I need to study for this maths test can u leave questions
ale4655 [162]
A camera has a listed price of $632.98 <span>before tax. If the sales tax rate is </span><span>6.75%, find the total cost of the camera with sales tax included. Round your answer to the nearest cent, as necessary.</span>
3 0
3 years ago
What is p divided by 5 in a algebraic expression​
KiRa [710]

P/5

Step-by-step explanation:

p will be a numerator then 5 will be a denominator since it's p divided by 5.

8 0
3 years ago
Solve the system <br> 2x+2y+z=-2 <br> -x-2y+2z=-5<br> 2x+4y+z=0
drek231 [11]

The values of (x,y,z) are (3,-1,-2) , if the given are equations 2x+2y+z=- 2,-x-2y+2z=-5 and 2x+4y+z=0.

Step-by-step explanation:

The given is,

                          2x+2y+z=- 2.......................................(1)

                         -x-2y+2z=-5......................................(2)

                            2x+4y+z=0.........................................(3)

Step:1

           Equation (2) is multiplied by -1            ( Eqn(2) × -1 )

                                         x+2y-2z=5.............................(4)

          Subtract the equation (1) and (4)

                                        2x+2y+z=- 2

                                         x+2y-2z=5

                 ( - )

           (2x-x)+(2y-2y)+(z+2z)=(-2-5)

                                                  x+3z=-7......................(5)

Step:2

          Equation (2) is multiplied by -2                 ( Eqn(2) × -2)

                                        2x+4y-4z=10........................(6)

         Subtract equation (6) and (3),                  

                                        2x+4y-4z=10

                                         2x+4y+z=0

                   ( - )

       (2x-2x)+(4y-4y)+(-4z-z)= (10-0)

                                                     -5z=10

                                                         z = - \frac{10}{5}

                                                         z = -2

         From the equation (5),

                                                  x+3z=-7  

                                          x+(3)(-2)=-7

                                                           x = -7+6

                                                            x = -1

         From equation (1),

                                            2x+2y+z=- 2

          Substitute x and z values,

                               (2)(-1)+2y+(-2)=-2

                                                     2y - 4=2

                                                           2y=4-2

                                                           2y=2

                                                            y=\frac{2}{2}

                                                             y = 1

Step:3

                Check for solution,

                                  -x-2y+2z=-5

                Substitute x,y and z values,

               -(-1)-(2)(1)+(2)(-2)=-5

                                         1-2-4=-5

                                                    -5 = -5

Result:

              The values of (x,y,z) are (3,-1,-2) , if the given are equations 2x+2y+z=- 2,-x-2y+2z=-5 and 2x+4y+z=0.

8 0
3 years ago
What is the volume of the cylinder if the height is 2x+7 and the radius is x-3
shusha [124]

Answer:

Therefore the volume of the cylinder=\pi(2x^3-5x^2-24x+63)  cubic units

Step-by-step explanation:

Given height of a cylinder is (h) =2x+7

and radius  (r)= x-3

Volume of the cylinder = \pi r^2 h

                                  =\pi (x-3)^2(2x+7)

                                  =\pi (x^2-6x+9)(2x+7)

                                  =\pi (2x^3-12x^2+18x+7x^2-42x+63)

                                  =\pi(2x^3-5x^2-24x+63)  cubic units

Therefore the volume of the cylinder=\pi(2x^3-5x^2-24x+63)  cubic units

5 0
3 years ago
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