Question

Hope an expert can.help with this. thanx

Answer 1

Taking care of units first:

4000cm = 40m

700cm = 7m

Let's find the area then:

A1 = Area of Small Rectangle = $length*width$

A2 = Area of Large Rectangle = $length*width$

A3 = Area of Semi-Circle = $\frac{\pi r^{2}}{2}$

$A=A1+A2+A3\\A=(lw) + (lw) + (\frac{\pi r^{2}}{2})\\A=[(10)(40)]+[(68)(33)]+[\frac{\pi r^{17}}{2}]\\A=(400)+(2244)+(8.5\pi)\\A=8.5\pi +2644\\A=(26.7)+2644\\A=26.7+2644\\A=2670.7m^{2}$

Then, to find the perimeter:

$P=40+68+33+34+7+10+(\frac{2\pi r}{2})\\P=192+(\pi r)\\P=192+(17\pi)\\P=192+53.4\\P=245.4m$

In summary:

$P=245.4m\\A=2670.7m^{2}$