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2 years ago

Find the measure of angle y. Round your answer to the nearest hundredth. (please type the numerical answer only) (6 points)

Mathematics

1 answer:

Ymorist [56]2 years ago

5 0

Sin (y) = 4/20
y = sin⁻¹(4/20)
y = 11.54°

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The equation below represents Function A and the graph represents Function B:

Snezhnost [94]

Answer:

Slope of Function B = – Slope of Function A

Step-by-step explanation:

Slope of function A= $-2$

Slope of function B=$\frac{3-1}{3-2}=2$

6 0

2 years ago

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A piece of fabric is 2 yards long. The fabric is cut into 24 pieces of equal length. How long is each piece?

Vera_Pavlovna [14]

Answer:

48 Yards long

Step-by-step explanation: You multiply 24x 2

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2 years ago

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Please help if you can :)

crimeas [40]

The graph is Parabola or Graph of Quadratic Function.

The graph has minimum value, not maximum. So ( A ) is not correct for maximum part.

B is not correct for exponential part.

also C is not correct for discrete part as Quadratic graph is continuous.

So the answer is D.

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2 years ago

cos theta = 4/5, 0˚< theta < 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta

NikAS [45]

First calculate $\sin\theta$ .

$\sin^2\theta+\cos^2\theta=1\\\\\sin^2\theta=1-\cos^2\theta\\\\\sin^2\theta=1-\left(\dfrac{4}{5}\right)^2\\\\\\\sin^2\theta=1-\dfrac{16}{25}\\\\\\\sin^2\theta=\dfrac{9}{25}\quad|\sqrt{(\dots)}\\\\\\\sin\theta=\sqrt{\dfrac{9}{25}}\\\\\\\boxed{\sin\theta=\dfrac{3}{5}}$

We take positive value of sinθ because 0° < θ < 90°
Now we could calculate sin2θ, cos2θ and tan2θ:

$\sin2\theta=2\sin\theta\cos\theta=2\cdot\dfrac{3}{5}\cdot\dfrac{4}{5}=\dfrac{2\cdot3\cdot4}{5\cdot5}=\dfrac{24}{25}\\\\\\\cos2\theta=\cos^2\theta-\sin^2\theta=\left(\dfrac{4}{5}\right)^2-\left(\dfrac{3}{5}\right)^2=\dfrac{16}{25}-\dfrac{9}{25}=\dfrac{7}{25}\\\\\\
\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=\dfrac{\frac{24}{25}}{\frac{7}{25}}=\dfrac{24\cdot25}{7\cdot25}=\dfrac{24}{7}=3\dfrac{3}{7}$

5 0

2 years ago

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Someone please help?

PIT_PIT [208]

The last one is right

3 0

2 years ago