The gene flow would increment or quality stream would increment between the two parts, and speciation would not happen. The probability of speciation would diminish as qualities were shared between the two gatherings. Kept up quality stream between two populaces can likewise prompt a mix of the two quality pools, diminishing the hereditary variety between the two gatherings.
Ok so, here goes:
simple interest: r- rate, A- amount in the end, t- time, P- principal
<span>r = (1/t)(A/P - 1)
</span>Putting in our numbers
r = (1/4)((21236/5309) - 1) = 0.75
r = 0.75
Converting r decimal to R a percentage
R = 0.75 * 100 = 75%/year
The interest rate required to get a total amount, principal plus interest, of $21,236.00 from simple interest on a principal of $5,309.00 over 4 years is 75% per year.
Answer:
64√3 ft²
Step-by-step explanation:
The short leg of the triangle has length (8 ft)(cos 60°), or (8 ft)(1/2), or 4 ft.
The long leg (represented by the dashed line) is (8 ft)(sin 60°), or
(8 ft)(√3/2), or 4√3. This is also the width of the horizontal trapezoid.
The area of this horizontal trapezoid is:
(sum of horizontal sides)
A = ------------------------------------- * (width)
2
Here, the area is:
(18 ft + (18 ft - 4 ft)
= ------------------------------------- * (4√3)
2
32 ft
= ----------- * 4√3 = 64√3 ft²
2
Answer:
Size of groups known: First and last questions (The rice and cups ones)
Number of groups known: Second and third questions (Cars and hats)
Step-by-step explanation:
In the first problem, you know that one sack is one group, and it tells you that each sack weighs 3 kg. Therefore, you know the size of the group (or a sack).
In the last one, you know that a table is one group and each table fits 4 cups. So, you know that the size of the group is 4 cups.
In the second and third questions, you know that each group is a row (cars) or "equal group" (hat) and that there are 4 of each. So, you know that there are 4 of each group, meaning you know the "number of groups"
