Every function associates input values with output values. The domain of a function is the set of all the inputs the function accepts.
You will basically always find your function graphed with the inputs on the horizontal axis and the outputs on the vertical axis. This means that every point on the graph has coordinates
, and the domain is the set of all the x values.
The points on your red line have all coordinates
, where d starts from 0 and ranges up to 12. So, the domain of the function is ![[0,12]](https://tex.z-dn.net/?f=%20%5B0%2C12%5D%20)
<h3>
<em>Answer</em><em>:</em></h3><h2>
<em>3</em><em>2</em></h2>
<em>Solution</em><em>,</em>
<em>2</em><em>x</em><em>-</em><em>5</em><em>6</em><em>=</em><em>8</em>
<em>or,</em><em>2</em><em>x</em><em>=</em><em>8</em><em>+</em><em>5</em><em>6</em>
<em>or,</em><em>2</em><em>x</em><em>=</em><em>6</em><em>4</em>
<em>or,</em><em>X=</em><em>6</em><em>4</em><em>/</em><em>2</em>
<em>X=</em><em>3</em><em>2</em>
<em>Hope </em><em>it</em><em> helps</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
Answer:
Acceptable Range (in grams) is between 0.048 grams and 0.052 grams
Step-by-step explanation:
So, it means that the actual weight can be 0.002 grams LESS THAN or even GREATER than the idea weight.
So
0.05 + 0.002 = 0.052
and
0.05 - 0.002 = 0.048
Thus, the acceptable range will be BETWEEN 0.048 grams and 0.052 grams
The conic water vessel of height 40 cm and radius 8 cm filled at 20 cm^3/s gives;
- The rate at which the water level is rising when the water level is 12 cm from the vertex is approximately <u>1.1 cm/s</u>.
- When the vessel is one-quarter filled the rate at which the water level is rising is approximately <u>0.21 cm/s</u>.
<h3>How can the water level rate be found?</h3>
The volume of the vessel, v = π•r^2•h/3
![\frac{h}{r} = \frac{40}{8} = 5](https://tex.z-dn.net/?f=%20%5Cfrac%7Bh%7D%7Br%7D%20%20%3D%20%20%5Cfrac%7B40%7D%7B8%7D%20%20%3D%205)
h = 5•r
Therefore;
v = π•r^2•(h)/3 = π•(h/5)^2•h/3
v = π•h^3/75
By chain rule of differentiation, we have;
![\frac{dv}{dh} = \frac{dv}{dt} \times \frac{dt}{dh}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdv%7D%7Bdh%7D%20%20%3D%20%20%5Cfrac%7Bdv%7D%7Bdt%7D%20%20%20%5Ctimes%20%20%5Cfrac%7Bdt%7D%7Bdh%7D%20%20)
Which gives;
![π• \frac{ {h}^{2} }{25} = 20 × \frac{dt}{dh}](https://tex.z-dn.net/?f=%CF%80%E2%80%A2%20%5Cfrac%7B%20%7Bh%7D%5E%7B2%7D%20%7D%7B25%7D%20%3D%2020%20%C3%97%20%5Cfrac%7Bdt%7D%7Bdh%7D%20%20)
![\frac{dh}{dt} = \frac{20}{\pi \frac{ {h}^{2} }{25} }](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdh%7D%7Bdt%7D%20%20%3D%20%20%5Cfrac%7B20%7D%7B%5Cpi%20%5Cfrac%7B%20%7Bh%7D%5E%7B2%7D%20%7D%7B25%7D%20%7D%20)
When the height is 12 cm from the vertex, we have;
- The rate at which the water level is rising when the water level is 12 cm from the vertex is approximately <u>1.1 cm/s</u>.
When the vessel is one-quarter filled, we have;
v = π•h^3/75
π•(40)^3/(75×4) = π•h^3/75
10•(40)^2 = 16,000 = h^3
h = (16,000)^(1/3) = 25 (approx)
Which gives;
When the vessel is one-quarter filled the rate at which the water level is rising is approximately 0.21 cm/s.
Learn more about rate of change here:
brainly.com/question/20066447
I guess 145 because if u put the Anacreon to the partisan numer then multiply and minus 2 so = 145 <span />