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3 years ago

Terrence says pi is a rational number since it is the ratio of a circle's circumference to its diameter. Why is

Mathematics

1 answer:

kari74 [83]3 years ago

7 0

Answer:

(A) Pi cannot be written as a ratio of integers even if it represents a different ratio.

Step-by-step explanation:

A rational number is can be expressed as the quotient of two integers. It can either be a number with or without a decimal part when converted to decimals.

C = 2 $\pi$ r and D = 2r

C = $\pi$ D

Thus, $\pi$ = $\frac{C}{D}$

= $\frac{22}{7}$ = 3.142857143...

Terrence was incorrect because Pi is an irrational number which cannot be represented by a simple fraction without approximation.

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The total length of wires a b and c is 445 cm wire a is 45 cm longer then wire b and wire b is half as long as wire c how long i

Oksana_A [137]

Answer:

$a = 145\ cm$

Step-by-step explanation:

Given

$a + b + c = 445$

$a = 45 + b$

$b = \frac{1}{2}c$

Required

Determine the length of a

Solve for c in $b = \frac{1}{2}c$

$2 * b = \frac{1}{2}c * 2$

$2b = c$

$c = 2b$

Substitute $c = 2b$ and $a = 45 + b$ in $a + b + c = 445$

$a + b + c = 445$

$45 + b + b + 2b = 445$

$45 + 4b = 445$

Solve for 4b

$4b = 445 - 45$

$4b = 400$

Solve for b

$b = 400/4$

$b = 100$

Recall that: $a = 45 + b$

$a=45+100$

$a = 145\ cm$

6 0

4 years ago

Find the cube roots of 125(cos 288° + i sin 288°)

kow [346]

Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)

so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288

so r = 5 and 3O = 288 + 360p and O = 96 + 120p

so one cube root is 5 (cos 96 + i sin 96)

Im a little rusty at this stuff Its been a long time.

Im not sure of the other 2 roots

sorry cant help you any more

3 0

3 years ago

Read 2 more answers

How do you solve 5 is _____ % of 25

Aneli [31]

Let the missing % be x.

Now, according to your question ;

5 = x% of 25

5 = x / 100 * 25

thus, 25x = 500

Thus, x = 500/25

= 20

Thus, 5 is 20% of 25.

5 0

3 years ago

Read 2 more answers

Help please!

xxTIMURxx [149]

The answer is D. Three over two

8 0

3 years ago

Which of the following are factors of the equation when written in factored form

jasenka [17]

Answer:

B and D

Step-by-step explanation:

Given

2a² + 8a - 15 = 3a - 3 ( subtract 3a - 3 from both sides )

2a² + 5a - 12 = 0 ← in standard form

To factorise the quadratic

Consider the factors of the product of the a² term and the constant term which sum to give the coefficient of the a term, that is

product = 2 × - 12 = - 24 and sum = + 5

The factors are + 8 and - 3

Use these factors to split the a- term

2a² + 8a - 3a - 12 = 0 ( factor the first/second and the third/fourth terms )

2a(a + 4) - 3(a + 4) = 0 ← factor out (a + 4) from each term

(a + 4)(2a - 3) = 0 ← in factored form

4 0

4 years ago