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Amanda [17]
3 years ago
10

According to Internet security experts, approximately 90% of all e-mail messages are spam (unsolicited commercial e-mail), while

the remaining 10% are legitimate. A system administrator wishes to see if the same percentages hold true for the e-mail traffic on her servers. She randomly selects e-mail messages and checks to see whether or not each one is legitimate. (Unless otherwise specified, round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Assuming that 90% of the messages on these servers are also spam, compute the probability that the first legitimate e-mail she finds is the fifth message she checks:
Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

0.0656

Step-by-step explanation:

For each message, we have these following probabilities:

90% probability it is spam.

10% probability it is legitimate.

Compute the probability that the first legitimate e-mail she finds is the fifth message she checks:

The first four all spam, each with a 90% probability.

The fifth legitimate, with a 10% probability.

P = (0.9)^{4} \times 0.1 = 0.0656

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Crispy Clover, a popular vegetarian restaurant, introduced a new menu that has 20%, percent more dishes than the previous menu.
Elden [556K]

Correct answers are D + D(\frac{1}{5}) and 1.2D i.e. Options A & D

<u>Step-by-step explanation:</u>

Options for this questions are:

A)D+1/5D

B)D+20

C)D+20D

D)1.2D choose two answers.

We have , Crispy Clover, a popular vegetarian restaurant, introduced a new menu that has 20%, percent more dishes than the previous menu. The previous menu had D dishes.We need to find expressions could represent how many dishes Crispy Clover's new menu has . Let's find out:

Initially , Number of dishes are D . Then 20% more dishes are there in menu

⇒ \frac{D(20)}{100}

So , Total Number of Dishes are

⇒ D + \frac{20d}{100}

⇒ D + \frac{20d}{20(5)}

⇒ D + D(\frac{1}{5})

⇒ D + D(0.2)

⇒ 1.2D

Therefore, Correct answers are D + D(\frac{1}{5}) and 1.2D i.e. Options A & D .

4 0
3 years ago
Simultaneous equations 2x+3y=13 4x-y=-2
Rufina [12.5K]

Answer:

(0.5, 4 )

Step-by-step explanation:

Given the 2 equations

2x + 3y = 13 → (1)

4x - y = - 2 → (2)

Multiplying (2) by 3 and adding to (1) will eliminate the term in y

12x - 3y = - 6 → (3)

Add (1) and (3) term by term to eliminate y

14x = 7 ( divide both sides by 14 )

x = 0.5

Substitute x = 0.5 into either of the 2 equations and evaluate for y

Substituting into (1)

2(0.5) + 3y = 13

1 + 3y = 13 ( subtract 1 from both sides )

3y = 12 ( divide both sides by 3 )

y = 4

Solution is (0.5, 4 )

3 0
3 years ago
Coach Kiefer budgeted $300 to take his team to a semi-pro baseball game. He bought each of the 13 players a ticket for $7.25 a h
valina [46]

Answer:

answer is 13.86.. .....

3 0
2 years ago
2 triangles are shown. The first triangle has side lengths 35, 20, and 20. The second triangle has side lengths x, 44, 44.
Svet_ta [14]
The value of x should be 59 to make the triangles similar.
7 0
3 years ago
Read 2 more answers
The sum of the first 10 terms of an arithmetic series is 100 and the sum of next 10 300 .Find the series.​
Free_Kalibri [48]

Let a be the first term in the sequence, and d the common difference between consecutive terms. If aₙ denotes the n-th term in the sequence, then

a₁ = a

a₂ = a₁ + d = a + d

a₃ = a₂ + d = a + 2d

a₄ = a₃ + d = a + 3d

and so on, up to the n-th term

aₙ = a + (n - 1) d

The sum of the first 10 terms is 100, and so

\displaystyle \sum_{n=1}^{10} a_n = 100 \\ \sum_{n=1}^{10} (a + (n-1)d) = 100 \\ (a-d) \sum_{n=1}^{10} 1 + d \sum_{n=1}^{10} n = 100 \\ 10a+45d = 100

where we use the well-known sum formulas,

\displaystyle \sum_{n=1}^N 1 = 1 + 1 + 1 + \cdots + 1 = N

\displaystyle \sum_{n=1}^N n = 1 + 2 + 3 + \cdots + N = \frac{N(N+1)}2

The sum of the next 10 terms is 300, so

\displaystyle \sum_{n=11}^{20} a_n = 300 \\ (a-d) \sum_{n=11}^{20} 1 + d \sum_{n=11}^{20} n = 300 \\ (a-d) \left(\sum_{n=1}^{20} 1 - \sum_{n=1}^{10} 1\right) 1 + d \left(\sum_{n=1}^{20} n - \sum_{n=1}^{10} n\right) = 300 \\ 10a+145d = 300

Solve for a and d. Eliminating a gives

(10a + 145d) - (10a + 45d) = 300 - 100

100d = 200

d = 2

and solving for a gives

10a + 145×2 = 300

10a = 10

a = 1

So, the given sequence is simply the sequence of positive odd integers,

{1, 3, 5, 7, 9, …}

given recursively by the relation

\begin{cases}a_1 = 1 \\ a_n = a_{n-1} + 2 & \text{for }n>1\end{cases}

and explicitly by

a_n = 1 + 2(n-1) = 2n - 1

for n ≥ 1.

7 0
1 year ago
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