Answer:
y-2 = -2(x+1)
Step-by-step explanation:
Find the slope(m) first using the two points (3, -6) and (-1, 2).
Slope: -2
Next, plug in x₁ and y₁. I plugged in (-1, 2)
13) B. 8.47,8.67,8.7
14) A
Just ask for explanation if u need it
Hope that helped :)
Answer:
7m + 5
Step-by-step explanation:
1) Simplify.
(12m + 1) - 1 (5m - 4) -> (12m + 1) - 5m + 4
2) Eliminate unnecessary parenthesis.
(12m + 1) - 5m + 4 -> 12m + 1 - 5m + 4.
3) Combine like terms.
12m - 5m = 7m, 4 + 1 =5 -> 7m + 5
The solution is 7m + 5
What is the midline equation of the function g(x)=3\sin(2x-1)+4g(x)=3sin(2x−1)+4g, (, x, ), equals, 3, sine, (, 2, x, minus, 1,
Aleksandr-060686 [28]
Answer:
Required equation of midline is x=4.
Step-by-step explanation:
Given function is,

In standerd form (1) can be written as,

where,
|a|= amplitude.
b= vertical shift.
c= horizontal shift.
Midline is the line which runs between maximum and minimum value.
In this problem,
a=3, b=2, c=-1, d=4
So amplitude a=3 and graph is shifted 4 units in positive y-axis.
Therefore,
Maximum value = d + a = 4 + 3 = 7
Minumum value = d - a = 4 - 3 = 1
Midline will be centered of the region (7, 1) that is at 4.
Hence equation of midline is x=4.
Answer:
For A) it is possible that the speed the cat is going over the speed limit
For B) The statement is false as if the error is negative, the speed of the car will be less than the speed limit.
Step-by-step explanation:
Data provided in the question:
Maximum error on a car speedometer = 1.6% = 0.016
Maximum Speed limit on the road = 65 miles per hour
Now,
The error will be ± 1.6%
Now,
When the speedometer reads 64 miles per hour
The possible speed of the car can be
64 miles per hour + Error
= 64 + [0.016 × 64]
= 64 + 1.024
= 65.024 miles per hour
or
The speed can be
64 miles per hour - Error
= 64 - [0.016 × 64]
= 64 - 1.024
= 62.976 miles per hour
Hence,
For A) it is possible that the speed the cat is going over the speed limit
For B) The statement is false as if the error is negative, the speed of the car will be less than the speed limit.