p(x)= x-2
g(x)= 2x^3 + 3x^2 - 11x - 6
first we have to find the zero of the polynomial of x-2
p(x)= x-2 = 0
x=2
therefore,
p(x)= 2x^3 + 3x^2 - 11x - 6
p(2)= 2*2^3 + 3*2^2 - 11*2 - 6
= 2*8 + 3*4 - 11*2 - 6
= 16 + 12 - 22 - 6
= 28-28
= 0
Hope it helped u, ^_^.
Answer:
$50
Step-by-step explanation:
5= 26+4=30
6=30+4=34
7=34+4=38
8=38+4=42
9=42+4=46
10=46+4=50
(x - 2)² + (y - 6)² = 4
You can be certain about one thing just by looking at the equation (2, 6) is the center, so, obviously the circle isnt going through this point
Since the radius is 2 if we don't move from y = 6 we have points in (0, 6) and (4, 6)
So alternative b.
To be more certain just subs the point in the x and y, if its equal, it pass through
(x - 2)² + (y - 6)² = 4
To point (4, 6)
(4 - 2)² + (6 - 6)² = 4
(2²) + 0² = 4
4 = 4
Thats right
Answer:
C.
Step-by-step explanation:
Negative exponents on the top is equivalent to them being positive in the bottom.
