1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lisov135 [29]
2 years ago
7

How long is 50% of 60 minutes?

Mathematics
2 answers:
ElenaW [278]2 years ago
6 0

Answer:

30 minutes

Step-by-step explanation:

60 divided by 2 = 30

lable min

butalik [34]2 years ago
3 0

Answer:

it's 30 minutes sorry if am wrong

You might be interested in
Let f be a function. Use each statement to find the coordinates of a point on the graph of f. f (5) = 9
omeli [17]

Answer:

400

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Use this list of Basic Taylor Series and the identity sin2θ= 1 2 (1−cos(2θ)) to find the Taylor Series for f(x) = sin2(3x) based
notsponge [240]

Answer:

The Taylor series for sin^2(3 x) = - \sum_{n=1}^{\infty} \frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}, the first three non-zero terms are 9x^{2} -27x^{4}+\frac{162}{5}x^{6} and the interval of convergence is ( -\infty, \infty )

Step-by-step explanation:

<u>These are the steps to find the Taylor series for the function</u> sin^2(3 x)

  1. Use the trigonometric identity:

sin^{2}(x)=\frac{1}{2}*(1-cos(2x))\\ sin^{2}(3x)=\frac{1}{2}*(1-cos(2(3x)))\\ sin^{2}(3x)=\frac{1}{2}*(1-cos(6x))

   2. The Taylor series of cos(x)

cos(y) = \sum_{n=0}^{\infty}\frac{-1^{n}y^{2n}}{(2n)!}

Substituting y=6x we have:

cos(6x) = \sum_{n=0}^{\infty}\frac{-1^{n}6^{2n}x^{2n}}{(2n)!}

   3. Find the Taylor series for sin^2(3x)

sin^{2}(3x)=\frac{1}{2}*(1-cos(6x)) (1)

cos(6x) = \sum_{n=0}^{\infty}\frac{-1^{n}6^{2n}x^{2n}}{(2n)!} (2)

Substituting (2) in (1) we have:

\frac{1}{2} (1-\sum_{n=0}^{\infty}\frac{-1^{n}6^{2n}x^{2n}}{(2n)!})\\ \frac{1}{2}-\frac{1}{2} \sum_{n=0}^{\infty}\frac{-1^{n}6^{2n}x^{2n}}{(2n)!}

Bring the factor \frac{1}{2} inside the sum

\frac{6^{2n}}{2}=9^{n}2^{2n-1} \\ (-1^{n})(9^{n})=(-9^{n} )

\frac{1}{2}-\sum_{n=0}^{\infty}\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}

Extract the term for n=0 from the sum:

\frac{1}{2}-\sum_{n=0}^{0}\frac{-9^{0}2^{2*0-1}x^{2*0}}{(2*0)!}-\sum_{n=1}^{\infty}\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}\\ \frac{1}{2} -\frac{1}{2} -\sum_{n=1}^{\infty}\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}\\ 0-\sum_{n=1}^{\infty}\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}\\ sin^{2}(3x)=-\sum_{n=1}^{\infty}\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}

<u>To find the first three non-zero terms you need to replace n=3 into the sum</u>

sin^{2}(3x)=\sum_{n=1}^{\infty}\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}\\ \sum_{n=1}^{3}\frac{-9^{3}2^{2*3-1}x^{2*3}}{(2*3)!} = 9x^{2} -27x^{4}+\frac{162}{5}x^{6}

<u>To find the interval on which the series converges you need to use the Ratio Test that says</u>

For the power series centered at x=a

P(x)=C_{0}+C_{1}(x-a)+C_{2}(x-a)^{2}+...+ C_{n}(x-a)^{n}+...,

suppose that \lim_{n \to \infty} |\frac{C_{n}}{C_{n+1}}| = R.. Then

  • If R=\infty, the the series converges for all x
  • If 0 then the series converges for all |x-a|
  • If R=0, the the series converges only for x=a

So we need to evaluate this limit:

\lim_{n \to \infty} |\frac{\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}}{\frac{-9^{n+1}2^{2*(n+1)-1}x^{2*(n+1)}}{(2*(2n+1))!}} |

Simplifying we have:

\lim_{n \to \infty} |-\frac{(n+1)(2n+1)}{18x^{2} } |

Next we need to evaluate the limit

\lim_{n \to \infty} |-\frac{(n+1)(2n+1)}{18x^{2} } |\\ \frac{1}{18x^{2} } \lim_{n \to \infty} |-(n+1)(2n+1)}|}

-(n+1)(2n+1) is negative when n -> ∞. Therefore |-(n+1)(2n+1)}|=2n^{2}+3n+1

You can use this infinity property \lim_{x \to \infty} (ax^{n}+...+bx+c) = \infty when a>0 and n is even. So

\lim_{n \to \infty} |-\frac{(n+1)(2n+1)}{18x^{2} } | \\ \frac{1}{18x^{2}} \lim_{n \to \infty} 2n^{2}+3n+1=\infty

Because this limit is ∞ the radius of converge is ∞ and the interval of converge is ( -\infty, \infty ).

6 0
2 years ago
If the two sides of one triangle are proportional to two sides of another triangle ande their included angles are congruent then
Ray Of Light [21]

if two of the sides are proportional and the included angles are congruent  then the triangles are SIMILAR.

Answer: similar

3 0
3 years ago
Will give you brainiest
BabaBlast [244]

Answer:

\boxed{

\boxed{

Step-by-step explanation:

A) If AB is a diameter, Then ACB is a 90 degrees angle because In a semi-circle (AB is a diameter which divides the circle into 2 equal parts), the angle opposite to the diameter is of 90 degrees.

So, <ACB = 90 degrees

Then <a = 180-90-28

=> <a = 62 degrees

B) The opposite interior angles of a quadrilateral inscribed in a circle add up to 180 degrees.

So,

=> <a + <b = 180

=> <b = 180-62

=> <b = 118 degrees

3 0
2 years ago
The ratio of boys to girls in the class is 4 to 5. If there are 18 boys and girls in the
bearhunter [10]

Answer:

8 boys and 10 girls

Step-by-step explanation:

If the ratio is 4:5,

4x2 + 5x2 equal 8+10 =

18.

4:5=8:10

7 0
3 years ago
Read 2 more answers
Other questions:
  • Choose all the weights that are equal to 1 ton 200 pounds.
    11·1 answer
  • Margo has 3 blue marbles, 4 green marbles,and 5 red marbles in a bag. She randomly selects one marble. What is the probability t
    12·2 answers
  • 16 is divided by the sum of a number q and 1. The result is 4. What is the number?
    8·1 answer
  • A bag of cookies can be shared equally among 2,,3,4,5, or 6 friends. What is the least number of cookies the bag could have?
    13·1 answer
  • If the temperature outside is 25 Celsius what clothing would be the most appropriate
    13·2 answers
  • Find the inner product for (-8,2) (4.5,18) and state whether the vectors are perpendicular.
    11·1 answer
  • Enter the amplitude of the function f(x) . f(x)=3/4cos(3x)+4
    14·2 answers
  • Keith needs to drive a total of 18 miles. So far, he has driven 9.4 miles. How many more miles must Keith drive?
    9·2 answers
  • Please answer ASAP please
    8·1 answer
  • Identify the slope of the graphed line:
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!