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lisov135 [29]
3 years ago
7

How long is 50% of 60 minutes?

Mathematics
2 answers:
ElenaW [278]3 years ago
6 0

Answer:

30 minutes

Step-by-step explanation:

60 divided by 2 = 30

lable min

butalik [34]3 years ago
3 0

Answer:

it's 30 minutes sorry if am wrong

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Consider the following formula used to estimate the height, h, of a seeding after w weeks since planting h=(1/5)w + (8/5)which o
Bogdan [553]

Answer:

w=5h-8

Step-by-step explanation:

Take the original formula h=(1/5)w+(8/5)

Subtract -8/5 on both sides to isolate the w, so h-8/5=(1/5)w

Now you have to get rid of the 1/5, so multiply 5(h-8/5), the 5 in the 8/5 cross each other out. You are left with 5h-8

7 0
3 years ago
Evaluate the following expression . 2*[4+(12+16)/7
Nataliya [291]

Answer:

16

Step-by-step explanation:

2 \times (4 + (12 + 16) \div 7  \\ (12 + 16) = 28 \div 7 = 4 + 4 = 8 \\ 2 \times 8 = 16

3 0
2 years ago
8p+8=10+7p what is the solution set
Evgesh-ka [11]
The answer is:  "p = 2" .
______________________________________________________
Explanation:
______________________________________________________
Given:
______________________________________________________
  " 8p + 8 = 10 + 7p " ;   Solve for "p" ; 

Subtract "7p" from each side of the equation; & subtract "8" from each side of the equation; as follows:

8p + 8 − 7p − 8 = 10 + 7p − 7p <span>− 8 ; 
</span>
to get: 
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"p = 2 " ;  which is our answer.
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8 0
3 years ago
Read 2 more answers
Will mark brainliest PLEASE HELP!!! 20 points
Fudgin [204]

Answer:

B. reflected across tge x axis

3 0
3 years ago
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First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
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