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Murljashka [212]

3 years ago

12

Hey peeps I'm doing online school this year and right now I'm just not motivated. Any advice on how to get motivated?

2 answers:

frez [133]3 years ago

7 0

LOLOLOL I'm not very motivated either, but you taking aEsThEtIc notes. I often find that when I take prettier notes, I become more productive. Also, maybe if you're not listening to your teachers, you can block sites. Or if your school gave you a chromebook you can use that. You can also find a way that you actually find online school <em>fun</em>. I remember when online school started for me, my friends and I would join this meet and talk bad about the teachers and work on our tests together. Also, you can find a way to get better lighting or something. I am always insecure about my lighting (cause it S U C K S), but if you fix your lighting, you won't really have to worry about that. Other than that the main thing is to just focus like you were in regular school.

mafiozo [28]3 years ago

3 0

Answer:

something that motivates me is music

Step-by-step explanation:

since I can't work with music that makes me sing i listen to lofi music. try listening to chilled cow lofi study music

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-9=k/6-8<br><br> can anyone help please.

AleksAgata [21]

Answer:

k=18

Step-by-step explanation:

have a good day :)

7 0

3 years ago

Read 2 more answers

What is the area of a semicircle with the diameter of 12 in.

natita [175]

Radius r = 6 in
so area A = 6x6xπx0.5 = 18π
note: a semicircle is just half of a full circle:)

7 0

3 years ago

Read 2 more answers

2. The alkalinity of a fluid (pH) can be modeled in terms of its hydrogen ion concentration (H+, measured in moles/liter) of the

nataly862011 [7]

Given the equation:

$pH=-log\mleft(H^+\mright)$

You know that a lab technician finds that a sample of fluid has this pH:

$pH=4.5$

Then, in order to find the hydrogen ion concentration of the fluid, you need to follow these steps:

1. Substitute the pH given in the exercise into the equation:

$4.5=-log(H^+)$

Multiply both sides by -1:

$-4.5=\log (H^+)$

2. Solve for:

$H^+$

Remember that, by definition:

$\log _b\mleft(c\mright)=a\Rightarrow b^a=c$

In this case, you can identify that:

$\begin{gathered} a=-4.5 \\ b=10 \\ c=H^+ \end{gathered}$

Hence, substituting values and simplifying, you get:

$\begin{gathered} b^a=c \\ 10^{-4.5}=H^+ \\ H^+=0.00003162278\text{ }\frac{moles}{liter} \end{gathered}$

Therefore, the answer is:

$H^+=0.00003162278\text{ }\frac{moles}{liter}$

4 0

2 years ago

On a winter day in Alaska, the temperature at noon was -0.6°C. From noon to 3:00, the temperature increased by 1.2°C. From 3:00

vazorg [7]

The expression is -6 + 1.2 + -0.4 + -0.6

7 0

3 years ago

At the moment, a physical therapist has 9 9/12 rolls of medical tape on hand. He anticipates using up 6 6/12 rolls while working

mart [117]

Answer:

subtract 6.5 by 9.75

Step-by-step explanation:

9/12 =.75

6/12=.5

9.75-6.5=3.25

hope this helps

°_°

3 0

3 years ago