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kkurt [141]
3 years ago
13

What are the solutions of this quadratic equation? x2 − 10x = -34

Mathematics
2 answers:
Gemiola [76]3 years ago
7 0
Here it is, step by step:

x^2 - 10x = -34
x^2 - 10x + 34 = 0
We cannot easily factor anything, so we resort to the quadratic equation. The work is attached as an image.
yKpoI14uk [10]3 years ago
7 0

Answer:

x=5+3i or x=5-3i

Step-by-step explanation:

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List down all the values of k<br>if; - 4≤ k ≤ 1​
vekshin1

Answer:

All the values of k are  -4, -3, -2, -1, 0 , 1

Step-by-step explanation:

Given;

- 4≤ k ≤ 1​

The range of value of k is between -4 and 1.

These values are listed as follows;

k = -4, -3, -2, -1, 0 , 1

Therefore, all the values of k are  -4, -3, -2, -1, 0 , 1

6 0
3 years ago
Mr. Gardener invested $500,000. His annual interest was $40,000. What was the annual interest rate?
Archy [21]

Mr. Gardener's annual interest rate is 8%.

40,000/500,000 = 0.08

8 0
3 years ago
Plss view the image :((((((((((
topjm [15]

Answer:

f(x) = -8

Step-by-step explanation:

f(x) = x² + 2x – 8

f(x) = (-2)² + 2(-2) – 8

f(x) = (-2)² + 2(-2) – 8

f(x) = 4 + (-4) – 8

f(x) = 4 – 4 – 8

f(x) = 0 – 8

f(x) = -8

I hope this helps

8 0
3 years ago
A triangle has the coordinates
fiasKO [112]

Answer:

coordinates of its image

A' = ( -4, -1)

B' =( -3, -3)

C' = ( 0, 2)

Step-by-step explanation:

Reflect in y-axis means mirror it's points in the y -axis.

This means that the x coordinate of each point, changes only. Any mirrored point in the y-axis, will change only, by multiplying the x-coordinate by -1.

(Remember, zero multiplied by -1 remains 0).

Given are these points A, B, and C.

A = (4, -1)

B = (3,-3)

C = (0, 2)

After mirroring in the y- axis you get:

A' = ( -4, -1)

B' =( -3, -3)

C' = ( 0, 2)

8 0
3 years ago
Find lim h→0 f(2+h)-f(2)/h if f(x)=x^2+x+1
bekas [8.4K]

Answer:

5

Step-by-step explanation:

\displaystyle \lim_{h \to 0} \frac{f(2+h)-f(2)}{h}

\displaystyle\lim_{h \to 0} \frac{(2+h)^2 + 2 + h + 1 - 2^2 - 2 - 1}{h}

\displaystyle\lim_{h \to 0} \frac{4 + 4h + h^2 + h - 4}{h}

\displaystyle\lim_{h \to 0} \frac{h^2 + 5h}{h}

\displaystyle\lim_{h \to 0} h + 5

= 5

8 0
3 years ago
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