Answer:
The program in Python is as follows:
num = int(input())
for i in str(num):
print(int(i))
Explanation:
This gets input for the number
num = int(input())
This converts the number to string and iterates through each element of the string
for i in str(num):
This prints individual digits
print(int(i))
Answer:
The time complexity of the code is O(log₇n).
Explanation:
The i is updated by 7*i.On each iteration i is multiplied by 7.So on finding the time complexity of the code given above it will come out to be log base 7.
When we divide the input by 2 the time complexity is log base 2.
So on dividing it by 7 we get the time complexity of log base 7.
A program that is required to three (3) numbers. calculate and print their total is given below:
<h3>The Program</h3>
import java.util.Scanner;
public class SumAndAverage {
public static void main(String[ ] args) {
System.out.println("Enter three numbers - ");
// Accepting and finding sum of numbers.
int sum = 0;
Scanner sc = new Scanner(System.in);
for (int i = 0; i < 3; i++)
sum += sc.nextInt( );
// Printing sum and average.
System.out.println("Sum - " + sum);
System.out.println("Average - " + (sum / 3f));
}
}
The output would request three different numbers, then add them up, and display the output of the sum and then display or print their total
Read more about programming here:
brainly.com/question/23275071
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The answer is d.mother board
The amount paid regularly for insurance is called the premium.
