Seems to be an arythmetic sequence
Sn=[n(a1+an)]/2
where
Sn means sum of all terms up the nth term
n=number of terms
a1=first term
an=nth term
so from 86 to the 22th term is from a1 to a22
find teh sequence
miknus 7 each time
an=a1+d(n-1)
an=87-7(n-1)
find 22n term
a22=87-7(22-1)
a22=87-7(21)
a22=87-147
a22=-60
S22=[22(87-60)]/2
S22=[22(27)]/2
S22=594/2
S22=297
the sum is 297
Answer and Step-by-step explanation:
A) The first three terms are:
5, 8, 11
B) The tenth term is 32
You find the answer by plugging in the value for n. So for A), you would plug in 1, 2, and 3 (the first 3 terms), then to find the tenth term, you plug in 10 for n.
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That's my answer Brainliest me!
Answer:
$31.5
Step-by-step explanation:
Answer:
the answer is 22 hope this helps
Step-by-step explanation:
7(-7)= -49
-49+149=100
100-56=44
44/2=22
