Ms hadley has an orange tree when she lived in california .less than 39 of the oranges were lost during the first month i need h
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"Isolate the constant by adding 7 to both sides of the equation."
This step separates the non-squareable 7 and the squareable
.
"Add 9 to both sides of
to form a perfect square trinomial while keeping the equation balanced."
After separating the non-squareable, add the number which makes the first or left side a perfect square trinomial. The formula to find the number is:
.
When we plug the values:
Simplify:
"Write the trinomial
as 
squared."
When you factor , you will get 
.
"Use the square root property of equality to get
."
The 16 is coming from the part when we add 9. We needed 9 on the left side for a perfect square, but to protect the balance of the equality, we need to add 9 to the right side too. When we add 7 and 9, we got 16, and that is where it came from.
"Isolate the variable x to get solutions of -1 and 7."
To isolate x we branched the plus-minus sign:
This step separates the non-squareable 7 and the squareable
"Add 9 to both sides of
After separating the non-squareable, add the number which makes the first or left side a perfect square trinomial. The formula to find the number is:
When we plug the values:
Simplify:
"Write the trinomial
When you factor
"Use the square root property of equality to get
The 16 is coming from the part when we add 9. We needed 9 on the left side for a perfect square, but to protect the balance of the equality, we need to add 9 to the right side too. When we add 7 and 9, we got 16, and that is where it came from.
"Isolate the variable x to get solutions of -1 and 7."
To isolate x we branched the plus-minus sign:
distribution of the total number of tumors produced in the whole population over a one-year period by this kind of radiation is 0, 1, 2, ..................104000.
let, x denote the total number of hits,
y denotes the number of hits by a particle in a year or an individual,
one per week ⇒ 52 per year
therefore, rate = 52 per year
since it is very rare to hit all individuals, we can use Poisson distribution.
therefore by using the formula p (x = x) = (e^(-rate) × rateˣ) ÷ x! ; x = 0, 1, 2, ............( 2000 × 52)
p (x = 2) = (e⁻⁵² × 52ˣ) ÷ x! ; x = 0, 1, 2, ............104000
now each hit has a harm of probability 10⁻⁵.
so p(total no. of tumors produced over a one year period)
= {e⁻⁵² × 52ˣ} ÷ x! × 10⁻⁵ ; x = 0, 1, 2, ............104000
therefore total no. of tumors = 2000 × (e⁻⁵² × ) ÷ x! × xⁿ ; x = 0, 1, 2, ............104000
Know more about Poisson distribution here: brainly.com/question/17280826
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(complete question)
Assume that each of the 2000 individuals living near a nuclear power plant is exposed to particles of a certain kind of radiation at an average rate of one per week. Suppose that each hit by a particle is harmless with a probability of 1 - 10⁻⁵, and produces a tumor with a probability of 10⁻⁵. Find the approximate distribution of the total number of tumors produced in the whole population over a one-year period by this kind of radiation.