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shtirl [24]
3 years ago
5

Gisele has $5.90 in quarters and nickels. If Gisele has 16 more nickels than quarters, how many quarters does she have? [I don't

want the answer I just want to know how to set the problem up please]

Mathematics
1 answer:
krok68 [10]3 years ago
3 0

Answer:

See below

Step-by-step explanation:

Quarters= 25(x)

Nickels =5(x+16)

25x+5(x+16)=590 (no decimal)

If you solve for x, you’ll get the number of quarters.

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Answer:

D

Step-by-step explanation:

3/7 + 6/7 = 9/7

Change 9/7 to a mixed number = 1 2/7

Add your whole numbers: 1 + 10 + 1 = 12

Answer: 12 2/7

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3.125 as a fraction is 25/8
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One of ten different prizes was randomly put into each box of a cereal. If a family decided to buy this cereal until it obtained
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Answer:

29.29

Step-by-step explanation:

The first trial among a distribution of independent trials with a constant success probability follows a geometric probability.

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At the first draw, we only selected one of the 10 prizes and so 1 draw gives a success

<em>E(X)=</em>1/<em>p</em>

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After the first prize is drawn, we are interested in the first time (success), that we draw another prize that is different (<em>p</em>=9/10)

E(X2)=1/9÷10

E(X2)= 10/9

After the first prizes have being drawn, we now interested in the first time success that we draw a different prize from the first 2

E(X3)=1/8÷10

E(X3)=10/8

E(X3)=5/4

After the first three prizes have been drawn, we are now interested in the success of a first time draw for the 4th different prize

E(X4)=1/7÷10

E(X4)=10/7

Fifth different prize

E(X5)=1/6÷10

E(X5)=10/6

E(X5)=5/3

Sixth different prize

E(X6)=1/5÷10

E(X6)=10/5

E(X6)=2

Seventh different prize

E(X7)=1/4÷10

E(X7)=10/4

E(X7)=5/2

Eighth different prize

E(X8)=1/3÷10

E(X8)=10/3

Ninth different prize

E(X9)=1/2÷10

E(X9)=10/2

E(X9)=5

After the 9 different prizes have been drawn, we are interested in the first time we will draw the tenth different prize

E(X10)=1/1÷10

E(X10)=10

Add up all corresponding values;

<em>E(X)=</em>E(X1)+E(X2)+E(X3)+E(X4)+E(X5)+E(X6)+E(X7)+E(X8)+E(X9)+E(X10)

<em>E(X)=</em>1+10/9+5/4+10/7+5/3+2+5/2+10/3+5+10

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4 0
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Answer:                

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The probability for success of an event is P(A), and the probability of success of a second, independent event is P(B). What is
Alborosie

Given:

The probability for success of an event is P(A)

The probability of success of a second, independent event is P(B).

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It is given that,

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3 years ago
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