Rate = 2 seats/11 minutes = 2/11 seats/min
Therefore the time required for s seats is
That is,
m = (11s)/2 min
When s = 16, obtain
When s = 19, obtain
Answers:
When s = 16, m = 88 min
When s = 19, m = 104.5 min
f(3) is where the line is on the Y axis when X is 3:
Looking at the red line when it passes over X3, the line is on Y8.
The answer is B.8
This is a common factor problem.
Pencils come in a pack of 12
Erasers come in a pack of 10
First, break the number into their prime factors(the idea is that we will break the number down into its smallest multiples, which are prime numbers):
10 = 2 * 5
12 = 2 * 2 *3
So now we take the unique multiples of each number, and when we multiply them together, we will get the smallest number that both 10 and 12 can be divided into(this is what the problem is asking for)
We have (2*2*3) that comes from 12, and the only unique number that comes from the 10 is (5)
So now, we multiply:
2*2*3*5=60
However, this isn't exactly out answer. Now we have to divide our answer by the number of each this in the pack to know how many packs to buy.
60/12=5 packs of pencils
60/10= 6 packs of erasers
I hope this helps. Let me know if you have any questions!!
Answer:
The missing factor is (9s+1)
Step-by-step explanation:
The missing factor is (9s+1) because of the following
(9s^2 + s) + (18s+2)
If we factor out s from 9s^2+s, we get s(9s+1).
If we factor out 2 from 18s+2, we get 2(9s+1)
putting these together, we get s(9s+1) + 2(9s+1). Factoring out the common term of 9s+1, we get (9s+1)(s+2). therefore, the missing factor is 9s+1
Answer:
dot
Step-by-step explanation:
