Answer:
db / dt = kb
this becomes b(t) = Ce^(kt)
C = 100, the initial population
P(1) = 420 = 100 e^(1k)
4.2 = e^k
ln 4.2 = k
a) thus, b(t) = 100 e^(t ln 4.2)
b) b(3) = 100 e^(3 ln 4.2)
c) growth constant will still be ln 4.2 (constant percentage of populatioin)
d) 10000 = 100 e^(t ln 4.2)
100 = e^(t ln 4.2)
ln 100 = t ln 4.2
t = ln 100 / ln 4.2
Step-by-step explanation:
<span>Simplifying
4x + 8y = 30.60
Solving
4x + 8y = 30.60
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-8y' to each side of the equation.
4x + 8y + -8y = 30.60 + -8y
Combine like terms: 8y + -8y = 0
4x + 0 = 30.60 + -8y
4x = 30.60 + -8y
Divide each side by '4'.
x = 7.65 + -2y
Simplifying
x = 7.65 + -2y</span>
Simplify:
(7/9)/(3/5)
Multiply the numerator by the reciprocal of the denominator, (7/9)/(3/5) = 7/9×5/3:
(7×5)/(9×3)
9×3 = 27:
(7×5)/27
7×5 = 35:
Answer: 35/27
To find the percent of the birdhouses occupied, divide the number of occupied birdhouses by how many birdhouses there are in total:
Convert this decimal into a percentage by multiplying by 100:
5.26% of the birdhouses are occupied.
Answer:
C
Step-by-step explanation:
You have to do change of y over change of x, substitute the numbers to get 0.30-0.90 for y then 1-3 for x, get -0.06/-2 and solve that to get 0.3 per pound per year, which is answer C
