Answer:
thanx for the reminder
Step-by-step explanation:
have a wonderful day :)
Answer:
sinA = ± ![\sqrt{1-cos^2A}](https://tex.z-dn.net/?f=%5Csqrt%7B1-cos%5E2A%7D)
Step-by-step explanation:
Using the Pythagorean identity
sin²A + cos²A = 1 ( subtract cos²A from both sides )
sin²A = 1 - cos²A ( take the square root of both sides )
sinA = ± ![\sqrt{1-cos^2A}](https://tex.z-dn.net/?f=%5Csqrt%7B1-cos%5E2A%7D)
This is the difference of squares. Formula is:
A² - B² = ( A - B ) · ( A + B )
9 - y² = 3² - y² = ( 3 - y ) · ( 3 + y )
I think C) y=x because a line that is parallel to y=0 would be y=x and if there isn’t a number in front of a variable then it equals 1x. So I would pick C. Hopefully this helps♥️.