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A graphing calculator shows the minimum to be located at the vertex of the quadratic, x = -2.5, and the maximum to be located at the right end of the interval.
The absolute maximum value of f(x) is ln(18) ≈ 2.89037.
The absolute minimum value of f(x) is ln(5.75) ≈ 1.74920.
The absolute maximum value of f(x) is ln(18) ≈ 2.89037.
The absolute minimum value of f(x) is ln(5.75) ≈ 1.74920.
Using the t-distribution, it is found that the 95% confidence interval for the mean number of people the houses were shown is (20.1, 27.9).
We have the <u>standard deviation for the sample</u>, hence the t-distribution is used to build the confidence interval. Important information are given by:
- Sample mean of
.
- Sample standard deviation of
.
- Sample size of
The confidence interval is:
In which t is the critical value for a <u>95% confidence interval with 23 - 1 = 22 df</u>, thus, looking at a calculator or at the t-table, it is found that t = 2.0739.
Then:
The 95% confidence interval for the mean number of people the houses were shown is (20.1, 27.9).
A similar problem is given at brainly.com/question/15180581